Acetylacetone, abbreviated acacH, is a bidentate ligand. It loses a proton and coordinates as acac \(^{-}\), as shown below, where \(\mathrm{M}\) is a transition metal: Which of the following complexes are optically active: cis\(\mathrm{Cr}(\mathrm{acac})_{2}\left(\mathrm{H}_{2} \mathrm{O}\right)_{2}\), trans \(-\mathrm{Cr}(\mathrm{acac})_{2}\left(\mathrm{H}_{2} \mathrm{O}\right)_{2}\), and \(\mathrm{Cr}(\mathrm{acac})_{3} ?\)

Short Answer

Expert verified
Among the given complexes, cis-Cr(acac)2(H2O)2 and Cr(acac)3 are optically active, whereas trans-Cr(acac)2(H2O)2 is not optically active.

Step by step solution

01

Examine the cis-Cr(acac)2(H2O)2 complex

In the cis configuration, the two acac ligands and the two H2O molecules are located in adjacent positions (90° apart) around the metal center. To determine whether this complex is chiral, we should visualize its mirror image and analyze whether the two structures are superimposable or not. If the mirror images are not superimposable, the complex is chiral and therefore optically active.
02

Examine the trans-Cr(acac)2(H2O)2 complex

In the trans configuration, the two acac ligands and the two H2O molecules are in opposite positions (180° apart) around the metal center. Similar to the cis configuration, we should visualize the mirror image of the trans complex and assess whether the two structures can be superimposed. If not, the complex is chiral and optically active.
03

Examine the Cr(acac)3 complex

For this complex, there are three bidentate acac ligands coordinating to the transition metal. To determine whether this complex is optically active, we need to visualize its mirror image and check if the two structures are superimposable. If they are not, the complex is chiral and optically active.
04

Identify optically active complexes

After examining the three complexes and their mirror images, we can determine which of them are chiral and therefore optically active: 1. cis-Cr(acac)2(H2O)2: The metal center in this complex is a chiral center, as the mirror image is not superimposable onto the original molecule. Hence, this complex is optically active. 2. trans-Cr(acac)2(H2O)2: In contrast to the cis configuration, the mirror image of the trans configuration is superimposable onto the original molecule. Therefore, the metal center in this complex is not a chiral center, and the complex is not optically active. 3. Cr(acac)3: The mirror image of this complex is not superimposable onto the original molecule, indicating that the metal center is a chiral center. As a result, the complex is optically active. To conclude, out of the three given complexes, cis-Cr(acac)2(H2O)2 and Cr(acac)3 are optically active, while trans-Cr(acac)2(H2O)2 is not.

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Most popular questions from this chapter

Ammonia and potassium iodide solutions are added to an aqueous solution of \(\mathrm{Cr}\left(\mathrm{NO}_{3}\right)_{3} .\) A solid is isolated (compound A), and the following data are collected: i. When \(0.105 \mathrm{~g}\) of compound \(\mathrm{A}\) was strongly heated in \(\mathrm{ex}\) cess \(\mathrm{O}_{2}, 0.0203 \mathrm{~g} \mathrm{CrO}_{3}\) was formed. ii. In a second experiment it took \(32.93 \mathrm{~mL}\) of \(0.100 \mathrm{M} \mathrm{HCl}\) to titrate completely the \(\mathrm{NH}_{3}\) present in \(0.341 \mathrm{~g}\) compound \(\mathrm{A}\). iii. Compound A was found to contain \(73.53 \%\) iodine by mass. iv. The freezing point of water was lowered by \(0.64^{\circ} \mathrm{C}\) when \(0.601 \mathrm{~g}\) compound \(\mathrm{A}\) was dissolved in \(10.00 \mathrm{~g} \mathrm{H}_{2} \mathrm{O}\left(K_{\mathrm{f}}=\right.\) \(\left.1.86^{\circ} \mathrm{C} \cdot \mathrm{kg} / \mathrm{mol}\right)\) What is the formula of the compound? What is the structure of the complex ion present? (Hints: \(\mathrm{Cr}^{3+}\) is expected to be sixcoordinate, with \(\mathrm{NH}_{3}\) and possibly \(\mathrm{I}^{-}\) as ligands. The \(\mathrm{I}^{-}\) ions will be the counterions if needed.)

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