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Chapter 22: Problem 52

Draw structural formulas for each of the following alcohols. Indicate whether the alcohol is primary, secondary, or tertiary. a. 1 -butanol c. 2 -methyl-1-butanol b. 2 -butanol d. 2-methyl-2-butanol

Short Answer

Expert verified
a. 1-butanol: CH3-CH2-CH2-CH2-OH (Primary) b. 2-butanol: CH3-CH(OH)-CH2-CH3 (Secondary) c. 2 -methyl-1-butanol: CH3-CH2-CH(CH3)-CH2-OH (Primary) d. 2-methyl-2-butanol: CH3-CH(OH)-CH(CH3)-CH3 (Tertiary)

Step by step solution

01

a. 1 -butanol

1-butanol is an alcohol with four carbon atoms. It has the molecular formula C4H9OH. The structure can be drawn as follows: CH3-CH2-CH2-CH2-OH 1-butanol is a primary alcohol because the hydroxyl group (OH) is attached to a carbon that is bonded to only one other carbon.
02

b. 2 -butanol

2-butanol is an alcohol with four carbon atoms. It has a molecular formula C4H9OH. The structure can be drawn as follows: CH3-CH(OH)-CH2-CH3 2-butanol is a secondary alcohol because the hydroxyl group (OH) is attached to a carbon that is bonded to two other carbon atoms.
03

c. 2 -methyl-1-butanol

2-methyl-1-butanol is an alcohol with five carbon atoms. It has the molecular formula C5H12O. The structure can be drawn as follows: CH3-CH2-CH(CH3)-CH2-OH 2-methyl-1-butanol is a primary alcohol because the hydroxyl group (OH) is attached to a carbon that is bonded to only one other carbon atom.
04

d. 2-methyl-2-butanol

2-methyl-2-butanol is an alcohol with five carbon atoms. It has the molecular formula C5H12O. The structure can be drawn as follows: CH3-CH(OH)-CH(CH3)-CH3 2-methyl-2-butanol is a tertiary alcohol because the hydroxyl group (OH) is attached to a carbon that is bonded to three other carbon atoms.

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