Oxidation of an aldehyde yields a carboxylic acid: Draw the structures for the products of the following oxidation reactions. a. propanal \(\stackrel{[0 x]}{\longrightarrow}\) b. 2,3 -dimethylpentanal \(\stackrel{[0 \times]}{\longrightarrow}\) c. 3 -ethylbenzaldehyde \(\frac{[\operatorname{lox}]}{\longrightarrow}\)

The given compound is propanal, which has the structure \(CH_3 - CH_2 - CHO\). When propanal undergoes oxidation, it forms a carboxylic acid with the same number of carbon atoms. The product is propanoic acid, with the structure \(CH_3 - CH_2 - COOH\).

The given compound is 2,3-dimethylpentanal, which has the structure \((CH_3)_2 - CH - CH_2 - CH_2 - CHO\). When this aldehyde undergoes oxidation, it forms a carboxylic acid with the same number of carbon atoms. The product is 2,3-dimethylpentanoic acid, with the structure \((CH_3)_2 - CH - CH_2 - CH_2 - COOH\).

The given compound is 3-ethylbenzaldehyde, which has a benzene ring with an aldehyde group at one position, and an ethyl group at the third position from the aldehyde group. The structure is: \[ \begin{array}{c} \hspace{0.6cm}\overset{\displaystyle{CHO}}{\underset{\displaystyle{|}}{C}}\\ \hspace{1.5cm}|\\ \hspace{1.5cm}C -CH_3\\ \hspace{0.6cm}\overset{\displaystyle{C}}{\underset{\displaystyle{|}}{C}}\\ \hspace{1.5cm}|\\ \hspace{0.6cm}\overset{\displaystyle{C}}{\underset{\displaystyle{|}}{C}} \end{array} \] When this aldehyde undergoes oxidation, it forms a carboxylic acid with the same number of carbon atoms. The product is 3-ethylbenzoic acid, with the structure: \[ \begin{array}{c} \hspace{0.6cm}\overset{\displaystyle{COOH}}{\underset{\displaystyle{|}}{C}}\\ \hspace{1.5cm}|\\ \hspace{1.5cm}C -CH_3\\ \hspace{0.6cm}\overset{\displaystyle{C}}{\underset{\displaystyle{|}}{C}}\\ \hspace{1.5cm}|\\ \hspace{0.6cm}\overset{\displaystyle{C}}{\underset{\displaystyle{|}}{C}} \end{array} \]