Consider samples of phosphine \(\left(\mathrm{PH}_{3}\right.\) ), water \(\left(\mathrm{H}_{2} \mathrm{O}\right)\), hydrogen sulfide \(\left(\mathrm{H}_{2} \mathrm{~S}\right)\), and hydrogen fluoride (HF), each with a mass of \(119 \mathrm{~g}\). Rank the compounds from the least to the greatest number of hydrogen atoms contained in the samples.

Short Answer

Expert verified
The ranking of the compounds from least to greatest number of hydrogen atoms is: Hydrogen fluoride (HF) with \(3.58\times10^{24}\) atoms, Hydrogen sulfide (H2S) with \(4.20\times10^{24}\) atoms, Phosphine (PH3) with \(6.51\times10^{24}\) atoms, and finally Water (H2O) with \(7.96\times10^{24}\) atoms.

Step by step solution

01

Determine the molar mass of each compound

Using the periodic table, we can find the molar mass of each element and then calculate the molar mass of the compounds: - Phosphine (PH3): 1 P + 3 H = 30.97 + 3(1.01) = 33.00 g/mol - Water (H2O): 2 H + 1 O = 2(1.01) + 16.00 = 18.02 g/mol - Hydrogen sulfide (H2S): 2 H + 1 S = 2(1.01) + 32.07 = 34.08 g/mol - Hydrogen fluoride (HF): 1 H + 1 F = 1.01 + 19.00 = 20.01 g/mol
02

Calculate the moles of each compound

Using the mass (119 g) and molar mass from Step 1, we can calculate the moles of each compound: - Moles of PH3: \(\frac{119 g}{33.00 g/mol} = 3.61 \thinspace mol\) - Moles of H2O: \(\frac{119 g}{18.02 g/mol} = 6.61 \thinspace mol\) - Moles of H2S: \(\frac{119 g}{34.08 g/mol} = 3.49 \thinspace mol\) - Moles of HF: \(\frac{119 g}{20.01 g/mol} = 5.95 \thinspace mol\)
03

Calculate the number of moles of hydrogen in each sample

Now, we need to find out the moles of hydrogen atoms in each sample: - Moles of H in PH3: 3.61 mol * 3 = 10.83 mol - Moles of H in H2O: 6.61 mol * 2 = 13.22 mol - Moles of H in H2S: 3.49 mol * 2 = 6.98 mol - Moles of H in HF: 5.95 mol * 1 = 5.95 mol
04

Convert moles of hydrogen to the number of hydrogen atoms

Now we will convert the moles of hydrogen atoms to actual number of hydrogen atoms using Avogadro's number (6.022 x 10^23 atoms/mol): - Number of H atoms in PH3: \(10.83 \thinspace mol \times 6.022\times10^{23} \thinspace atoms/mol = 6.51\times10^{24} \thinspace atoms\) - Number of H atoms in H2O: \(13.22 \thinspace mol \times 6.022\times10^{23} \thinspace atoms/mol = 7.96\times10^{24} \thinspace atoms\) - Number of H atoms in H2S: \(6.98 \thinspace mol \times 6.022\times10^{23} \thinspace atoms/mol = 4.20\times10^{24} \thinspace atoms\) - Number of H atoms in HF: \(5.95 \thinspace mol \times 6.022\times10^{23} \thinspace atoms/mol = 3.58\times10^{24} \thinspace atoms\)
05

Rank the compounds from least to greatest number of hydrogen atoms

Now we can rank the compounds based on the number of hydrogen atoms found in Step 4: 1. Hydrogen fluoride (HF): \(3.58\times10^{24} \thinspace atoms\) 2. Hydrogen sulfide (H2S): \(4.20\times10^{24} \thinspace atoms\) 3. Phosphine (PH3): \(6.51\times10^{24} \thinspace atoms\) 4. Water (H2O): \(7.96\times10^{24} \thinspace atoms\) So, the ranking of the compounds from least to greatest number of hydrogen atoms is: HF < H2S < PH3 < H2O.

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Most popular questions from this chapter

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