What number of \(\mathrm{Fe}\) atoms and what amount (moles) of Fe atoms are in \(500.0 \mathrm{~g}\) of iron?

Short Answer

Expert verified
In 500 grams of iron, there are approximately 8.95 moles of Fe atoms and \(5.39 \times 10^{24}\) individual Fe atoms.

Step by step solution

01

Find the molar mass of iron (

Begin by finding the molar mass of iron, which is the mass of one mole of iron atoms. Based on the periodic table, the molar mass of iron (Fe) is approximately 55.84 g/mol.
02

Calculate the amount of iron in moles

Next, divide the mass of iron by the molar mass to find the amount of iron in moles: moles of Fe = (mass of Fe) / (molar mass of Fe) moles of Fe = \( \frac{500}{55.84} \) Now, calculate the moles of Fe: moles of Fe = \( \frac{500}{55.84} \) ≈ 8.95 moles
03

Calculate the number of iron atoms using Avogadro's number

Avogadro's number (Nₐ) is the number of atoms (or molecules, ions, etc.) in one mole of a substance, which is approximately \(6.022 \times 10^{23} \) entities per mole. To find the number of iron atoms, multiply the moles of iron by Avogadro's number: Number of Fe atoms = (moles of Fe) × (Avogadro's number) Number of Fe atoms = (8.95 moles) × \(6.022 \times 10^{23}\) atoms/mol Now, calculate the number of Fe atoms: Number of Fe atoms ≈ 5.39 × \(10^{24}\) iron atoms To summarize, there are approximately 8.95 moles of Fe atoms and \(5.39 \times 10^{24}\) individual Fe atoms in 500 grams of iron.

Unlock Step-by-Step Solutions & Ace Your Exams!

  • Full Textbook Solutions

    Get detailed explanations and key concepts

  • Unlimited Al creation

    Al flashcards, explanations, exams and more...

  • Ads-free access

    To over 500 millions flashcards

  • Money-back guarantee

    We refund you if you fail your exam.

Over 30 million students worldwide already upgrade their learning with Vaia!

One App. One Place for Learning.

All the tools & learning materials you need for study success - in one app.

Get started for free

Most popular questions from this chapter

Elixirs such as Alka-Seltzer use the reaction of sodium bicarbonate with citric acid in aqueous solution to produce a fizz: \(3 \mathrm{NaHCO}_{3}(a q)+\mathrm{C}_{6} \mathrm{H}_{8} \mathrm{O}_{7}(a q) \longrightarrow\) $$ 3 \mathrm{CO}_{2}(g)+3 \mathrm{H}_{2} \mathrm{O}(l)+\mathrm{Na}_{3} \mathrm{C}_{6} \mathrm{H}_{3} \mathrm{O}_{7}(a q) $$ a. What mass of \(\mathrm{C}_{6} \mathrm{H}_{8} \mathrm{O}_{7}\) should be used for every \(1.0 \times 10^{2}\) \(\mathrm{mg} \mathrm{NaHCO}_{3} ?\) b. What mass of \(\mathrm{CO}_{2}(\mathrm{~g})\) could be produced from such a mixture?

A given sample of a xenon fluoride compound contains molecules of the type \(\mathrm{XeF}_{n}\), where \(n\) is some whole number. Given that \(9.03 \times 10^{20}\) molecules of \(\mathrm{XeF}_{\text {a }}\) weigh \(0.368 \mathrm{~g}\), determine the value for \(n\) in the formula.

Arrange the following substances in order of increasing mass percent of nitrogen. a. NO b. \(\mathrm{N}_{2} \mathrm{O}\) c. \(\mathrm{NH}_{3}\) d. SNH

Calculate the percent composition by mass of the following compounds that are important starting materials for synthetic polymers: a. \(\mathrm{C}_{3} \mathrm{H}_{4} \mathrm{O}_{2}\) (acrylic acid, from which acrylic plastics are made) b. \(\mathrm{C}_{4} \mathrm{H}_{6} \mathrm{O}_{2}\) (methyl acrylate, from which Plexiglas is made) c. \(\mathrm{C}_{3} \mathrm{H}_{3} \mathrm{~N}\) (acrylonitrile, from which Orlon is made)

Phosphorus can be prepared from calcium phosphate by the following reaction: \(2 \mathrm{Ca}_{3}\left(\mathrm{PO}_{4}\right)_{2}(s)+6 \mathrm{SiO}_{2}(s)+10 \mathrm{C}(s) \longrightarrow\) \(6 \mathrm{CaSiO}_{3}(s)+\mathrm{P}_{4}(s)+10 \mathrm{CO}(g)\) Phosphorite is a mineral that contains \(\mathrm{Ca}_{3}\left(\mathrm{PO}_{4}\right)_{2}\) plus other non-phosphorus- containing compounds. What is the maximum amount of \(\mathrm{P}_{4}\) that can be produced from \(1.0 \mathrm{~kg}\) of phosphorite if the phorphorite sample is \(75 \% \mathrm{Ca}_{3}\left(\mathrm{PO}_{4}\right)_{2}\) by mass? Assume an excess of the other reactants.

See all solutions

Recommended explanations on Chemistry Textbooks

View all explanations

What do you think about this solution?

We value your feedback to improve our textbook solutions.

Study anywhere. Anytime. Across all devices.

Sign-up for free