A diamond contains \(5.0 \times 10^{21}\) atoms of carbon. What amount (moles) of carbon and what mass (grams) of carbon are in this diamond?

Short Answer

Expert verified
The diamond contains \(8.30 \times 10^{-3}\) moles of carbon and has a carbon mass of approximately 0.0997 grams.

Step by step solution

01

Identify the given values and constants

We are given the number of carbon atoms in the diamond: \(5.0 \times 10^{21}\). Avogadro's number, also known as the number of atoms/molecules in one mole, is \(6.022 \times 10^{23}\) entities per mole. The molar mass of carbon is 12.01 grams per mole.
02

Calculate the amount of carbon in moles

To find the amount of carbon in moles, we'll divide the given number of carbon atoms by Avogadro's number: Moles of carbon \(= \frac{5.0 \times 10^{21} \text{ atoms}}{6.022 \times 10^{23} \text{ atoms/mol}}\). Now, we can calculate the moles of carbon: Moles of carbon \(= \frac{5.0 \times 10^{21}}{6.022 \times 10^{23}} = 8.30 \times 10^{-3} \text{ mol}\).
03

Calculate the mass of carbon in grams

To find the mass of the carbon, we'll multiply the number of moles by the molar mass of carbon: Mass of carbon \(= (8.30 \times 10^{-3} \text{ mol}) \times (12.01 \text{ g/mol})\). Now, we can calculate the mass of carbon: Mass of carbon \(= (8.30 \times 10^{-3}) \times (12.01) = 0.0997 \text{ g}\).
04

Present the final answer

The diamond contains \(8.30 \times 10^{-3}\) moles of carbon and has a carbon mass of approximately 0.0997 grams.

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Avogadro's Number
Understanding Avogadro's number is essential when delving into the field of chemistry, particularly when discussing the mole concept. Avogadro's number, approximately equal to \(6.022 \times 10^{23}\), represents the quantity of atoms, ions, or molecules contained in one mole of any substance.

When students encounter problems involving the mole concept, the first step is usually to determine the relationship between the number of particles they have and how many moles they represent. This value is fundamental in bridging the gap between the macroscopic world we can measure and the atomic world that we cannot observe directly.

For instance, in the exercise provided, the task involves converting atoms to moles. By dividing the given number of carbon atoms, \(5.0 \times 10^{21}\), by Avogadro's number, we find the amount of substance in moles. This step is pivotal for subsequent calculations involving mass or volume in chemistry.
Molar Mass
Molar mass plays a crucial role in quantifying substances in chemical reactions and forms a bridge between mass in grams and amount in moles. It's defined as the mass of one mole of a substance, usually expressed in grams per mole (g/mol). The molar mass of each element is found on the periodic table and is based on the weighted average of all naturally occurring isotopes of that element.

In our sample exercise, the molar mass of carbon is stated as 12.01 g/mol. Knowing this value allows us to convert moles of a substance to the corresponding mass in grams - a frequently performed task in both theoretical study and practical laboratory work.

For example, after determining the number of moles of carbon in the diamond, the next step is to calculate its mass by multiplying the number of moles by the molar mass of carbon. Understanding the concept of molar mass is not only vital for solving this problem but also for preparing solutions of known concentration, calculating yields in reactions, or analyzing elemental compositions.
Stoichiometry

Basics of Stoichiometry

The realm of stoichiometry is where we relate quantities of reactants and products in a chemical reaction. It's an area of chemistry that allows us to make predictions about the outcomes of reactions. To perform stoichiometric calculations, one must have a balanced chemical equation and must understand mole-to-mole relationships.

In practice, stoichiometry involves skills like converting grams to moles (using molar mass) and using Avogadro's number to convert between atoms or molecules and moles. It empowers us to predict the amounts of products formed from given reactants or, conversely, the amounts of reactants needed to form certain products.

Applying Stoichiometry

In the present exercise, while direct stoichiometry isn't used, the foundational concepts are still at play. We use Avogadro's number and molar mass to find out the number of moles and the mass of carbon in the diamond. This process is the crux of stoichiometric calculations - relating quantitative aspects of substances in a precise and predictable manner.

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Most popular questions from this chapter

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