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Chapter 3: Problem 50

The Freons are a class of compounds containing carbon, chlorine, and fluorine. While they have many valuable uses, they have been shown to be responsible for depletion of the ozone in the upper atmosphere. In 1991, two replacement compounds for Freons went into production: \(\mathrm{HFC}-134 \mathrm{a}\left(\mathrm{CH}_{2} \mathrm{FCF}_{3}\right)\) and HCFC-124 (CHCIFCF \(_{3}\) ). Calculate the molar masses of these two compounds.

Short Answer

Expert verified
The molar masses of HFC-134a (CH2FCF3) and HCFC-124 (CHCIFCF3) are 102.036 g/mol and 117.478 g/mol, respectively.

Step by step solution

01

Identify the number of each element in both compounds

For HFC-134a (CH2FCF3), there are 2 Hydrogens, 2 Carbons, and 4 Fluorine atoms. For HCFC-124 (CHCIFCF3), there are 1 Hydrogen, 2 Carbons, 1 Chlorine, and 3 Fluorine atoms.
02

Calculate the molar mass of each element in HFC-134a

Carbon (C): 2 (atoms) x 12.01 (g/mol) = 24.02 g/mol Hydrogen (H): 2 (atoms) x 1.008 (g/mol) = 2.016 g/mol Fluorine (F): 4 (atoms) x 19.00 (g/mol) = 76.00 g/mol
03

Add the molar masses of each element in HFC-134a to find its total molar mass

Total molar mass of HFC-134a: 24.02 g/mol (C) + 2.016 g/mol (H) + 76.00 g/mol (F) = 102.036 g/mol
04

Calculate the molar mass of each element in HCFC-124

Carbon (C): 2 (atoms) x 12.01 (g/mol) = 24.02 g/mol Hydrogen (H): 1 (atom) x 1.008 (g/mol) = 1.008 g/mol Chlorine (Cl): 1 (atom) x 35.45 (g/mol) = 35.45 g/mol Fluorine (F): 3 (atoms) x 19.00 (g/mol) = 57.00 g/mol
05

Add the molar masses of each element in HCFC-124 to find its total molar mass

Total molar mass of HCFC-124: 24.02 g/mol (C) + 1.008 g/mol (H) + 35.45 g/mol (Cl) + 57.00 g/mol (F) = 117.478 g/mol So the molar masses of HFC-134a and HCFC-124 are 102.036 g/mol and 117.478 g/mol, respectively.

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Most popular questions from this chapter

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