Log out Go to App
Go to App

Learning Materials

Features

Discover

Chapter 4: Problem 77

A student titrates an unknown amount of potassium hydrogen phthalate \(\left(\mathrm{KHC}_{8} \mathrm{H}_{4} \mathrm{O}_{4}\right.\), often abbreviated \(\mathrm{KHP}\) ) with \(20.46 \mathrm{~mL}\) of a \(0.1000-M \mathrm{NaOH}\) solution. KHP (molar mass \(=204.22 \mathrm{~g} /\) mol) has one acidic hydrogen. What mass of KHP was titrated (reacted completely) by the sodium hydroxide solution?

Short Answer

Expert verified
The mass of KHP that reacted completely with the sodium hydroxide solution is approximately \(0.4177 \mathrm{~g}\).

Step by step solution

01

Write the balanced chemical equation.

The balanced chemical equation for the reaction between KHP and NaOH is as follows: KHP(aq) + NaOH(aq) ⟶ NaKP(aq) + H₂O(l) This tells us that one mole of KHP reacts with one mole of NaOH.
02

Determine the moles of NaOH in the solution.

Given the volume (20.46 mL) and concentration (0.1000 M) of NaOH, we can find the moles of NaOH in the solution by using the formula: moles of NaOH = volume (in L) × concentration moles of NaOH = (20.46 / 1000) × 0.1000 moles of NaOH = 0.002046 mol
03

Determine the moles of KHP based on stoichiometric ratio.

Since one mole of KHP reacts with one mole of NaOH, we can conclude that the moles of KHP that reacted completely are the same as the moles of NaOH. moles of KHP = moles of NaOH moles of KHP = 0.002046 mol
04

Calculate the mass of KHP.

To find the mass of KHP that reacted completely, we'll use the given molar mass of KHP (204.22 g/mol) and the moles of KHP calculated in step 3. mass of KHP = moles of KHP × molar mass mass of KHP = 0.002046 mol × 204.22 g/mol mass of KHP = 0.4177 g So, the mass of KHP that reacted completely with the sodium hydroxide solution is approximately 0.4177 g.

Unlock Step-by-Step Solutions & Ace Your Exams!

  • Full Textbook Solutions

    Get detailed explanations and key concepts

  • Unlimited Al creation

    Al flashcards, explanations, exams and more...

  • Ads-free access

    To over 500 millions flashcards

  • Money-back guarantee

    We refund you if you fail your exam.

Start your free trial

Over 30 million students worldwide already upgrade their learning with Vaia!

One App. One Place for Learning.

All the tools & learning materials you need for study success - in one app.

Get started for free

Most popular questions from this chapter

Write the balanced formula equation for the acid-base reactions that occur when the following are mixed. a. potassium hydroxide (aqueous) and nitric acid b. barium hydroxide (aqueous) and hydrochloric acid c. perchloric acid \(\left[\mathrm{HClO}_{4}(a q)\right]\) and solid iron(III) hydroxide d. solid silver hydroxide and hydrobromic acid e. aqueous strontium hydroxide and hydroiodic acid

What mass of solid aluminum hydroxide can be produced when \(50.0 \mathrm{~mL}\) of \(0.200 \mathrm{M} \mathrm{Al}\left(\mathrm{NO}_{3}\right)_{3}\) is added to \(200.0 \mathrm{~mL}\) of \(0.100 \mathrm{M} \mathrm{KOH} ?\)

Citric acid, which can be obtained from lemon juice, has the molecular formula \(\mathrm{C}_{6} \mathrm{H}_{3} \mathrm{O}_{7} .\) A \(0.250-\mathrm{g}\) sample of citric acid dissolved in \(25.0 \mathrm{~mL}\) of water requires \(37.2 \mathrm{~mL}\) of \(0.105 \mathrm{M}\) \(\mathrm{NaOH}\) for complete neutralization. What number of acidic hydrogens per molecule does citric acid have?

Calculate the concentration of all ions present in each of the following solutions of strong electrolytes. a. \(0.0200\) mole of sodium phosphate in \(10.0 \mathrm{~mL}\) of solution b. \(0.300\) mole of barium nitrate in \(600.0 \mathrm{~mL}\) of solution c. \(1.00 \mathrm{~g}\) of potassium chloride in \(0.500 \mathrm{~L}\) of solution d. \(132 \mathrm{~g}\) of ammonium sulfate in \(1.50 \mathrm{~L}\) of solution

What volume of each of the following bases will react completely with \(25.00 \mathrm{~mL}\) of \(0.200 \mathrm{M} \mathrm{HCl}\) ? a. \(0.100 \mathrm{M} \mathrm{NaOH}\) b. \(0.0500 \mathrm{M} \mathrm{Sr}(\mathrm{OH})_{2}\) c. \(0.250 \mathrm{M} \mathrm{KOH}\)
See all solutions

Recommended explanations on Chemistry Textbooks

Nuclear Chemistry

Read Explanation

Organic Chemistry

Read Explanation

Chemical Analysis

Read Explanation

Inorganic Chemistry

Read Explanation

Ionic and Molecular Compounds

Read Explanation

Kinetics

Read Explanation
View all explanations

What do you think about this solution?

We value your feedback to improve our textbook solutions.

Study anywhere. Anytime. Across all devices.

Sign-up for free