Assuming gasoline is pure \(\mathrm{C}_{8} \mathrm{H}_{18}(l)\), predict the signs of \(q\) and \(w\) for the process of combusting gasoline into \(\mathrm{CO}_{2}(g)\) and \(\mathrm{H}_{2} \mathrm{O}(g)\).

Short Answer

Expert verified
In the combustion of gasoline (C8H18) into CO2 and H2O, the process is exothermic, releasing heat to the surroundings, making q < 0. As the volume increases during combustion, the system performs work on the surroundings, resulting in w < 0. Thus, the signs of q and w are both negative.

Step by step solution

01

Determine the balanced equation for the combustion of gasoline

First, we need to find the balanced chemical equation for the combustion of gasoline. The general equation for the combustion of a hydrocarbon is: \( \mathrm{C}_{n} \mathrm{H}_{m}(l) + \left(n + \frac{m}{4}\right) \mathrm{O}_{2}(g) \to n \mathrm{CO}_{2}(g) + \frac{m}{2} \mathrm{H}_{2} \mathrm{O}(g) \) For gasoline, the hydrocarbon involved is octane (C8H18), so we can write the balanced equation as: \( \mathrm{C}_{8} \mathrm{H}_{18}(l) + \left(8 + \frac{18}{4}\right) \mathrm{O}_{2}(g) \to 8 \mathrm{CO}_{2}(g) + 9 \mathrm{H}_{2} \mathrm{O}(g) \) Alternatively, substitute 8 for n and 18 for m in the general combustion equation.
02

Determine the sign of heat (q)

Since combustion is an exothermic process, it releases heat to the surroundings. Therefore, the sign of q is negative: q < 0
03

Determine the sign of work (w)

In the combustion process, the volume of the system increases as gasoline (liquid) is converted into gaseous products (CO2 and H2O). The system does work on the surroundings as it expands to accommodate the higher volume of gases. Therefore, the sign of w is also negative: w < 0
04

Conclusion

In the process of combusting gasoline (C8H18) into CO2 and H2O, both heat (q) and work (w) have negative signs, indicating the release of heat to the surroundings and the system doing work on the surroundings.

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Chemical Equation for Combustion
Understanding the chemical equation for the combustion of gasoline is crucial for grasping the process of converting fuel into energy. Gasoline, often approximated as octane \textbf{(C8H18)}), undergoes a complex reaction with oxygen \textbf{(O2)} from the air when ignited in an engine. The balanced chemical equation representing this combustion is written as:
\[ \mathrm{C}_{8} \mathrm{H}_{18}(l) + 12.5 \, \mathrm{O}_{2}(g) \rightarrow 8 \, \mathrm{CO}_{2}(g) + 9 \, \mathrm{H}_{2} \mathrm{O}(g) \]
In this equation, the coefficients indicate the number of moles of each substance that are involved. For every mole of octane burned, 12.5 moles of oxygen are required to produce 8 moles of carbon dioxide \textbf{(CO2)} and 9 moles of water \textbf{(H2O)}, both in gaseous form. It's paramount for students to note that balancing this chemical equation is a key step in understanding the stoichiometry of the combustion reaction – a concept that involves the quantitative relationships between the amounts of reactants used and products formed in a chemical reaction.
Exothermic Process
An exothermic process is characterized by the release of energy to the environment, which usually occurs in the form of heat. The combustion of gasoline is a classic example of an exothermic reaction. During this process, the chemical energy stored in the fuel is released when the carbon and hydrogen atoms in octane bond with oxygen to form carbon dioxide and water. This energy release is perceived as heat and, to a lesser extent, light.

Significance in Combustion

In the context of the combustion of gasoline, the release of energy explains why engines get hot and why heat is felt when touching the hood of a car after it has been running. The negative sign of heat (q) in thermochemical equations symbolizes this energy going out of the system, hence q < 0. For students, it's important to associate the exothermic nature of combustion with the practical outcomes, such as the warming of the engine and the exhaust gases that heat up the surroundings.
Thermochemistry
The branch of chemistry that deals with the energy changes accompanying chemical reactions is called thermochemistry. In the case of gasoline combustion, thermochemistry focuses on the quantities of heat (q) and work (w) involved in the reaction. The signs of these quantities can tell us a lot about the processes occurring.
Since the reaction is exothermic, the heat term (q) is negative, indicating that energy is released into the surroundings as heat. Simultaneously, as gaseous products are formed, the system expands and performs work on the surroundings, represented by a negative sign for work (w), so w < 0.
  • Heat Release (q): Negative because energy is released
  • Work Done (w): Negative because the system expands against the surroundings
A thorough understanding of these concepts helps students predict physical changes and energy flows in various chemical processes so that they can apply this knowledge to real-world applications, such as how a vehicle's engine harnesses the energy from fuel.

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Most popular questions from this chapter

Consider the following reaction: $$ 2 \mathrm{H}_{2}(g)+\mathrm{O}_{2}(g) \longrightarrow 2 \mathrm{H}_{2} \mathrm{O}(l) \quad \Delta H=-572 \mathrm{~kJ} $$ a. How much heat is evolved for the production of \(1.00 \mathrm{~mole}\) of \(\mathrm{H}_{2} \mathrm{O}(l)\) ? b. How much heat is evolved when \(4.03 \mathrm{~g}\) hydrogen are reacted with excess oxygen? c. How much heat is evolved when \(186 \mathrm{~g}\) oxygen are reacted with excess hydrogen? d. The total volume of hydrogen gas needed to fill the Hindenburg was \(2.0 \times 10^{8} \mathrm{~L}\) at \(1.0\) atm and \(25^{\circ} \mathrm{C}\). How much heat was evolved when the Hindenburg exploded, assuming all of the hydrogen reacted?

Consider the following changes: a. \(\mathrm{N}_{2}(g) \longrightarrow \mathrm{N}_{2}(l)\) b. \(\mathrm{CO}(g)+\mathrm{H}_{2} \mathrm{O}(g) \longrightarrow \mathrm{H}_{2}(g)+\mathrm{CO}_{2}(g)\) c. \(\mathrm{Ca}_{3} \mathrm{P}_{2}(s)+6 \mathrm{H}_{2} \mathrm{O}(l) \longrightarrow 3 \mathrm{Ca}(\mathrm{OH})_{2}(s)+2 \mathrm{PH}_{3}(g)\) d. \(2 \mathrm{CH}_{3} \mathrm{OH}(l)+3 \mathrm{O}_{2}(g) \longrightarrow 2 \mathrm{CO}_{2}(g)+4 \mathrm{H}_{2} \mathrm{O}(l)\) e. \(\mathrm{I}_{2}(s) \longrightarrow \mathrm{I}_{2}(g)\) At constant temperature and pressure, in which of these changes is work done by the system on the surroundings? By the surroundings on the system? In which of them is no work done?

At \(298 \mathrm{~K}\), the standard enthalpies of formation for \(\mathrm{C}_{2} \mathrm{H}_{2}(\mathrm{~g})\) and \(\mathrm{C}_{6} \mathrm{H}_{6}(l)\) are \(227 \mathrm{~kJ} / \mathrm{mol}\) and \(49 \mathrm{~kJ} / \mathrm{mol}\), respectively. a. Calculate \(\Delta H^{\circ}\) for $$ \mathrm{C}_{6} \mathrm{H}_{6}(l) \longrightarrow 3 \mathrm{C}_{2} \mathrm{H}_{2}(g) $$ b. Both acetylene \(\left(\mathrm{C}_{2} \mathrm{H}_{2}\right)\) and benzene \(\left(\mathrm{C}_{6} \mathrm{H}_{6}\right)\) can be used as fuels. Which compound would liberate more energy per gram when combusted in air?

A coffee-cup calorimeter initially contains \(125 \mathrm{~g}\) water at \(24.2^{\circ} \mathrm{C}\). Potassium bromide \((10.5 \mathrm{~g})\), also at \(24.2^{\circ} \mathrm{C}\), is added to the water, and after the KBr dissolves, the final temperature is \(21.1^{\circ} \mathrm{C}\). Calculate the enthalpy change for dissolving the salt in \(\mathrm{J} / \mathrm{g}\) and \(\mathrm{kJ} / \mathrm{mol}\). Assume that the specific heat capacity of the solution is \(4.18 \mathrm{~J} /{ }^{\circ} \mathrm{C} \cdot \mathrm{g}\) and that no heat is transferred to the surroundings or to the calorimeter.

A swimming pool, \(10.0 \mathrm{~m}\) by \(4.0 \mathrm{~m}\), is filled with water to a depth of \(3.0 \mathrm{~m}\) at a temperature of \(20.2^{\circ} \mathrm{C}\). How much energy is required to raise the temperature of the water to \(24.6^{\circ} \mathrm{C} ?\)

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