A system undergoes a process consisting of the following two steps: Step \(1:\) The system absorbs \(72 \mathrm{~J}\) of heat while \(35 \mathrm{~J}\) of work is done on it. Step 2: The system absorbs \(35 \mathrm{~J}\) of heat while performing \(72 \mathrm{~J}\) of work. Calculate \(\Delta E\) for the overall process.

Short Answer

Expert verified
The change in internal energy for the overall process, ΔE, can be calculated by adding the change in internal energy for each step: ΔE1 = 107 J and ΔE2 = -37 J. Therefore, ΔE_overall = ΔE1 + ΔE2 = 107 J + (-37 J) = \(70 \mathrm{~J}\).

Step by step solution

01

Calculate heat and work for Step 1 of the process

In Step 1, we are given that the system absorbs 72 J of heat and 35 J of work is done on it. Since work is being done on the system, it has a negative value. So, we have: Q1 = 72 J W1 = -35 J
02

Calculate heat and work for Step 2 of the process

In Step 2, the system absorbs 35 J of heat and performs 72 J of work. Since work is being done by the system, it has a positive value. So, we have: Q2 = 35 J W2 = 72 J
03

Calculate ΔE for each step using the first law of thermodynamics

Using the first law of thermodynamics, ΔE = Q - W, calculate the change in internal energy for each step: ΔE1 = Q1 - W1 = 72 J - (-35 J) = 72 J + 35 J = 107 J ΔE2 = Q2 - W2 = 35 J - 72 J = -37 J
04

Calculate ΔE for the overall process by adding the results of each step

Now, add the change in internal energy for each step to find the change in internal energy for the overall process: ΔE_overall = ΔE1 + ΔE2 = 107 J + (-37 J) = 70 J The change in internal energy for the overall process is 70 J.

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Most popular questions from this chapter

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