Order the atoms in each of the following sets from the least exothermic electron affinity to the most. a. \(\mathrm{N}, \mathrm{O}, \mathrm{F}\) b. Al, Si, \(\mathrm{P}\)

Short Answer

Expert verified
For set A, the order from the least exothermic electron affinity to the most is: \(N < O < F\). For set B, the order is: \(Al < Si < P\).

Step by step solution

01

Locating the atoms on the periodic table

Locate the elements nitrogen (N), oxygen (O), and fluorine (F) on the periodic table. They are all in the second period (row) and are in the following order: N, O, F.
02

Applying the electron affinity trend

Since all three elements are in the same period of the periodic table, we can apply the general trend of electron affinity increasing from left to right in the same period. This means that nitrogen (N) has the least exothermic electron affinity, followed by oxygen (O), and finally fluorine (F) with the most exothermic electron affinity.
03

Ordering the atoms based on electron affinity

Using the information from Steps 1 and 2, we can order the atoms in Set A from the least exothermic electron affinity to the most: N < O < F. #Set B: Al, Si, P#
04

Locating the atoms on the periodic table

Locate the elements aluminum (Al), silicon (Si), and phosphorous (P) on the periodic table. They are all in the third period (row) and are in the following order: Al, Si, P.
05

Applying the electron affinity trend

Since all three elements are in the same period of the periodic table, we can apply the general trend of electron affinity increasing from left to right in the same period. This means that aluminum (Al) has the least exothermic electron affinity, followed by silicon (Si), and finally phosphorous (P) with the most exothermic electron affinity.
06

Ordering the atoms based on electron affinity

Using the information from Steps 1 and 2, we can order the atoms in Set B from the least exothermic electron affinity to the most: Al < Si < P.

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