Although no currently known elements contain electrons in \(g\) orbitals in the ground state, it is possible that these elements will be found or that electrons in excited states of known elements could be in \(g\) orbitals. For \(g\) orbitals, the value of \(\ell\) is \(4 .\) What is the lowest value of \(n\) for which \(g\) orbitals could exist? What are the possible values of \(m_{\ell} ?\) How many electrons could a set of \(g\) orbitals hold?

Short Answer

Expert verified
The lowest value of n for which g orbitals could exist is n = 5, the possible values of mℓ are -4, -3, -2, -1, 0, 1, 2, 3, and 4, and a set of g orbitals can hold 18 electrons.

Step by step solution

01

Finding the lowest value of n where a g orbital can exist

According to the quantum numbers, the relation between n and ℓ is that ℓ can take values from 0 to n-1. For g orbitals, ℓ = 4. So we need to find the smallest value of n for which this condition holds. n - 1 >= 4 n >= 5 So, the lowest value of n for which g orbitals could exist is n = 5.
02

Finding possible values of mℓ

The value of the magnetic quantum number mℓ ranges from -ℓ to ℓ in integer steps. Since we know that for g orbitals, ℓ = 4, we can now find the possible values of mℓ: -4, -3, -2, -1, 0, 1, 2, 3, 4
03

Calculating the number of electrons a set of g orbitals can hold

To find the number of electrons a set of g orbitals can hold, we have to consider that each orbital can hold two electrons with opposite spins. We have calculated 9 possible values for mℓ, which means there are 9 orbitals in the set of g orbitals. Hence, the total number of electrons that a set of g orbitals can hold is 9 orbitals * 2 electrons/orbital = 18 electrons. In conclusion, the lowest value of n for which g orbitals could exist is n = 5, the possible values of mℓ are -4, -3, -2, -1, 0, 1, 2, 3, and 4, and the number of electrons a set of g orbitals can hold is 18 electrons.

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