The periodic table consists of four blocks of elements that correspond to \(s, p, d\), and \(f\) orbitals being filled. After \(f\) orbitals come \(g\) and \(h\) orbitals. In theory, if a \(g\) block and an \(h\) block of elements existed, how long would the rows of \(g\) and \(h\) elements be in this theoretical periodic table?

Short Answer

Expert verified
In the theoretical periodic table, the length of the rows for the hypothetical \(g\) and \(h\) blocks would be 18 and 22 elements, respectively. This is because \(g\) orbitals can hold a maximum of 18 electrons, while \(h\) orbitals can hold up to 22 electrons.

Step by step solution

01

According to the relationship between the types of orbitals and the maximum number of electrons, \(g\) orbitals can hold a maximum of 18 electrons. Therefore, the length of the row for the \(g\) block in the periodic table would be 18 elements. Step 2: Determine the maximum number of electrons in \(h\) orbitals

Similarly, the relationship between the types of orbitals and the maximum number of electrons indicates that \(h\) orbitals can hold a maximum of 22 electrons. Therefore, the length of the row for the \(h\) block in the periodic table would be 22 elements. In conclusion, if a \(g\) block and an \(h\) block of elements existed in the periodic table, the length of the rows for \(g\) and \(h\) elements would be 18 and 22 elements, respectively.

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