Assume that a hydrogen atom's electron has been excited to the \(n=5\) level. How many different wavelengths of light can be emitted as this excited atom loses energy?

Short Answer

Expert verified
The hydrogen atom's electron at the \(n=5\) level can make \(4\) different transitions to lower energy levels (from \(n=5\) to \(n=4\), \(n=3\), \(n=2\), or \(n=1\)), each emitting a distinct wavelength of light. Therefore, \(4\) different wavelengths of light can be emitted.

Step by step solution

01

Identify the Possible Transitions

Since the electron is at the n=5 level, it can make transitions to any of the lower energy levels (n=4, n=3, n=2, or n=1).
02

Calculate the Number of Transitions

Each transition from the n=5 level to a lower energy level will correspond to a different wavelength of light. We can represent the transitions as follows: 1. From n=5 to n=4 2. From n=5 to n=3 3. From n=5 to n=2 4. From n=5 to n=1 Each of these transitions will emit a different wavelength of light. Thus, the number of different wavelengths emitted from the n=5 level is 4. In general, for an electron at energy level n, it can make (n-1) distinct transitions as it loses energy, resulting in (n-1) different wavelengths of light. Therefore, the answer is \(4\) different wavelengths of light.

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