The elements Cu, O, La, Y, Ba, Tl, and Bi are all found in high-temperature ceramic superconductors. Write the expected electron configuration for these atoms.

Refer to a periodic table to find the atomic number (number of protons) of each element. This also corresponds to the number of electrons, presuming a neutral atom. 1. Copper (Cu) - Atomic number 29 2. Oxygen (O) - Atomic number 8 3. Lanthanum (La) - Atomic number 57 4. Yttrium (Y) - Atomic number 39 5. Barium (Ba) - Atomic number 56 6. Thallium (Tl) - Atomic number 81 7. Bismuth (Bi) - Atomic number 83

For each element, begin with the electron configuration of the previous noble gas and fill the orbitals accordingly. Keep in mind the Aufbau principle, Hund's rule, and Pauli exclusion principle. 1. Copper (Cu): \[1s^2 2s^2 2p^6 3s^2 3p^6 4s^2 3d^9\] However, copper prefers a half-filled 4s and fully filled 3d orbital, so the electron configuration will be:\[1s^2 2s^2 2p^6 3s^2 3p^6 4s^1 3d^{10}\] 2. Oxygen (O):\[1s^2 2s^2 2p^4\] 3. Lanthanum (La):\[1s^2 2s^2 2p^6 3s^2 3p^6 4s^2 3d^{10} 4p^6 5s^2 4d^{10} 5p^6 6s^2 5d^1\] 4. Yttrium (Y):\[1s^2 2s^2 2p^6 3s^2 3p^6 4s^2 3d^{10} 4p^6 5s^2 4d^{10} 5p^6 6s^2 4f^{14} 5d^1\] 5. Barium (Ba):\[1s^2 2s^2 2p^6 3s^2 3p^6 4s^2 3d^{10} 4p^6 5s^2 4d^{10} 5p^6 6s^2\] 6. Thallium (Tl):\[1s^2 2s^2 2p^6 3s^2 3p^6 4s^2 3d^{10} 4p^6 5s^2 4d^{10} 5p^6 6s^2 4f^{14} 5d^{10} 6p^1\] 7. Bismuth (Bi):\[1s^2 2s^2 2p^6 3s^2 3p^6 4s^2 3d^{10} 4p^6 5s^2 4d^{10} 5p^6 6s^2 4f^{14} 5d^{10} 6p^3\] The electron configurations of the elements are now determined and written in their respective format.