Predict the molecular structure (including bond angles) for each of the following. (See Exercises 111 and \(112 .\) ) a. \(\mathrm{ICl}_{5}\) b. \(\mathrm{XeCl}_{4}\) c. \(\mathrm{SeCl}_{6}\)

Short Answer

Expert verified
In conclusion, the molecular structures and bond angles for the given molecules are as follows: a. \(\mathrm{ICl}_{5}\): Square pyramidal, bond angles around 90 degrees and 120 degrees b. \(\mathrm{XeCl}_{4}\): Square planar, bond angles around 90 degrees c. \(\mathrm{SeCl}_{6}\): Octahedral, bond angles around 90 degrees and 180 degrees

Step by step solution

01

Identify the central atom, bond electron pairs, and lone electron pairs for each molecule.

For each molecule, we'll first identify the central atom and count the number of bond electron pairs and lone electron pairs on it. a. \(\mathrm{ICl}_{5}\): Central atom: Iodine (I) Bond electron pairs: 5 (one bond with each of the 5 chlorine atoms) Lone electron pairs: 1 (as 7 - 5 = 2; corresponds to one lone electron pair) b. \(\mathrm{XeCl}_{4}\): Central atom: Xenon (Xe) Bond electron pairs: 4 (one bond with each of the 4 chlorine atoms) Lone electron pairs: 2 (as 8 - 4 = 4; corresponds to two lone electron pairs) c. \(\mathrm{SeCl}_{6}\): Central atom: Selenium (Se) Bond electron pairs: 6 (one bond with each of the 6 chlorine atoms) Lone electron pairs: 0 (as 6 - 6 = 0; corresponds to zero lone electron pairs)
02

Predict the molecular structure and bond angles using VSEPR theory.

Now, we will use the VSEPR notation AXE, where A represents the central atom, X represents the bond electron pairs, and E represents the lone electron pairs. Then, we'll determine the molecular structure based on it. a. \(\mathrm{ICl}_{5}\): VSEPR notation: AX5E1 Molecular structure: Square pyramidal Bond angles: Approximately 90 degrees between equatorial atoms and axial atoms; approximately 120 degrees between two equatorial atoms. b. \(\mathrm{XeCl}_{4}\): VSEPR notation: AX4E2 Molecular structure: Square planar Bond angles: Approximately 90 degrees between any two adjacent chlorine atoms. c. \(\mathrm{SeCl}_{6}\): VSEPR notation: AX6E0 Molecular structure: Octahedral Bond angles: 90 degrees between any two adjacent chlorine atoms; 180 degrees between any two opposite chlorine atoms. In conclusion, the molecular structures and bond angles for the given molecules are as follows: a. \(\mathrm{ICl}_{5}\): Square pyramidal, bond angles around 90 degrees and 120 degrees b. \(\mathrm{XeCl}_{4}\): Square planar, bond angles around 90 degrees c. \(\mathrm{SeCl}_{6}\): Octahedral, bond angles around 90 degrees and 180 degrees

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Most popular questions from this chapter

Write Lewis structures and predict the molecular structures of the following. (See Exercises 111 and \(112 .\) ) a. \(\mathrm{OCl}_{2}, \mathrm{KrF}_{2}, \mathrm{BeH}_{2}, \mathrm{SO}_{2}\) b. \(\mathrm{SO}_{3}, \mathrm{NF}_{3}, \mathrm{IF}_{3}\) c. \(\mathrm{CF}_{4}, \mathrm{SeF}_{4}, \mathrm{KrF}_{4}\) d. \(\mathrm{IF}_{5}, \mathrm{AsF}_{5}\) Which of these compounds are polar?

Predict the molecular structure (including bond angles) for each of the following. a. \(\mathrm{SeO}_{3}\) b. \(\mathrm{SeO}_{2}\)

Which compound in each of the following pairs of ionic substances has the most exothermic lattice energy? Justify your answers. a. \(\mathrm{NaCl}, \mathrm{KCl}\) b. \(\mathrm{LiF}, \mathrm{LiCl}\) c. \(\mathrm{Mg}(\mathrm{OH})_{2}, \mathrm{MgO}\) d. \(\mathrm{Fe}(\mathrm{OH})_{2}, \mathrm{Fe}(\mathrm{OH})_{3}\) e. \(\mathrm{NaCl}, \mathrm{Na}_{2} \mathrm{O}\) f. \(\mathrm{MgO}\), BaS

Some of the important properties of ionic compounds are as follows: i. low electrical conductivity as solids and high conductivity in solution or when molten ii. relatively high melting and boiling points iii. brittleness iv. solubility in polar solvents How does the concept of ionic bonding discussed in this chapter account for these properties?

Which member of the following pairs would you expect to be more energetically stable? Justify each choice. a. \(\mathrm{NaBr}\) or \(\mathrm{NaBr}_{2}\) b. \(\mathrm{ClO}_{4}\) or \(\mathrm{ClO}_{4}^{-}\) c. \(\mathrm{SO}_{4}\) or \(\mathrm{XeO}_{4}\) d. \(\mathrm{OF}_{4}\) or \(\mathrm{SeF}_{4}\)

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