Does a Lewis structure tell which electrons come from which atoms? Explain.

Short Answer

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A Lewis structure does not indicate which electrons come from which atoms. It is a representation of a molecule or ion that shows the arrangement of atoms and the distribution of valence electrons around each atom, mainly focusing on the distribution of valence electrons and the overall arrangement of atoms to predict the shape and help understand the bonding of a molecule.

Step by step solution

01

Introduction to Lewis Structure

A Lewis structure is a representation of a molecule or ion that shows the arrangement of atoms and the distribution of valence electrons around each atom. Its main purpose is to help predict the shape and to understand the bonding of a molecule.
02

Representing Atoms and Electrons

In a Lewis structure, atoms are represented by their chemical symbols, with single, double, or triple lines between them to indicate bonds. Valence electrons are shown as dots placed around the atoms.
03

Source of Electrons

A Lewis structure does not indicate which electrons come from which atoms. Electrons are shared between bonded atoms to achieve a stable octet (or duet for hydrogen), but the structure does not show the original source of these electrons.
04

Importance of Lewis Structure

Even though a Lewis structure does not show which electrons belong to which atoms, it remains a helpful tool for understanding the chemical bonding and molecular geometry of a molecule or ion. The main focus is on the distribution of valence electrons and the overall arrangement of atoms.

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Most popular questions from this chapter

Use the following data to estimate \(\Delta H_{\mathrm{f}}^{\circ}\) for magnesium fluoride. Lattice energy $$ \begin{aligned} \mathrm{Mg}(s)+\mathrm{F}_{2}(g) \longrightarrow & \mathrm{MgF}_{2}(s) \\ &-2913 \mathrm{~kJ} / \mathrm{mol} \end{aligned} $$ First ionization energy of \(\mathrm{Mg} \quad 735 \mathrm{~kJ} / \mathrm{mol}\) Second ionization energy of \(\mathrm{Mg} \quad 1445 \mathrm{~kJ} / \mathrm{mol}\) \(\begin{array}{ll}\text { Electron affinity of } \mathrm{F} & -328 \mathrm{~kJ} / \mathrm{mol}\end{array}\) Bond energy of \(\mathrm{F}_{2}\) \(154 \mathrm{~kJ} / \mathrm{mol}\) Enthalpy of sublimation for \(\mathrm{Mg}\) 150. \(\mathrm{kJ} / \mathrm{mol}\)

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