Compare and contrast bonding molecular orbitals with antibonding molecular orbitals.

Short Answer

Expert verified
Bonding molecular orbitals form from the constructive interaction of atomic orbitals, resulting in increased electron density between nuclei, lower energy levels, and stronger bonds. In contrast, antibonding molecular orbitals arise from destructive interaction of atomic orbitals, leading to decreased electron density, higher energy levels, and weaker bonds. Overall bond strength and stability depend on the occupancy of these orbitals.

Step by step solution

01

Introduction to Molecular Orbitals

Molecular orbitals are formed when atomic orbitals of individual atoms combine to form new orbitals. These new orbitals, called molecular orbitals, can be bonding or antibonding, depending on the type of interaction between the atomic orbitals and the energy levels of the resulting orbitals.
02

Formation of Bonding and Antibonding Molecular Orbitals

Bonding molecular orbitals occur when atomic orbitals from two atoms interact constructively, resulting in an increase in electron density between the two nuclei. This increased electron density lowers the energy of the system and strengthens the bond between the atoms. Antibonding molecular orbitals, on the other hand, occur when atomic orbitals interact destructively, causing a decrease in electron density between the nuclei. This results in a higher energy state and weakens the bond.
03

Energy Levels of Bonding and Antibonding Molecular Orbitals

Bonding molecular orbitals generally have lower energy levels than the original atomic orbitals because the constructive interaction leads to a more stable, lower energy state. Antibonding molecular orbitals, conversely, have higher energy levels than the atomic orbitals due to the destructive interaction and decreased stability.
04

Bond Strength and Stability

The relative strength and stability of a bond are influenced by the occupancy of bonding and antibonding molecular orbitals. If there are more electrons in bonding molecular orbitals, the overall bond will be stronger and more stable. Conversely, if there are more electrons in antibonding molecular orbitals, the bond will be weaker and less stable.
05

Comparison and Contrast Summary

In summary, bonding molecular orbitals form through constructive interaction of atomic orbitals and result in increased electron density between nuclei, lower energy levels, and stronger bonds. In contrast, antibonding molecular orbitals form through destructive interaction, leading to decreased electron density, higher energy levels, and weaker bonds. RoundedRectangleBorder

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Bonding Molecular Orbitals
When we talk about bonding molecular orbitals (BMOs), we're delving into the heart of why certain chemicals bind together the way they do. These are special kinds of molecular orbitals that are formed when atomic orbitals, which are regions of space around an atom where electrons are likely found, combine in a constructive manner. Imagine atomic orbitals as waves: when two waves meet in phase, their amplitudes add up, and we have a bigger wave. Similarly, when atomic orbitals from two atoms overlap in a synchronized way, electron density increases between the nuclei.

This increase has two significant consequences. First, it lowers the energy of the system as electrons are pulled into the space between the nuclei, creating what we consider a chemical bond. Second, it strengthens the bond between the atoms involved because the shared electrons help to hold the nuclei together. This is why BMOs are associated with the holding of a molecular structure, allowing for the stability that is so essential in chemistry.
Antibonding Molecular Orbitals
In contrast to bonding molecular orbitals, antibonding molecular orbitals (ABMOs) are what you might think of as the antiheroes of molecular interaction. These emerge when atomic orbitals combine destructively, meaning they meet out of phase, reducing the electron density where you would typically want it between the nuclei. This out-of-sync interaction can be likened to two opposing waves clashing and canceling each other out, leading to a trough where there should've been a crest.

The consequence of reduced electron density is a system with higher energy, which is less stable and generally unfavorable. ABMOs are higher in energy compared to both the original atomic orbitals and the BMOs because this configuration increases the repulsion between the nuclei. While BMOs act to hold two atoms together, ABMOs, if occupied by electrons, can actually work to push the atoms apart, thereby weakening the bond and, in some cases, preventing bond formation altogether. It's the delicate balance between the electrons in bonding and antibonding orbitals that ultimately influences the strength and existence of chemical bonds.
Interaction of Atomic Orbitals
Understanding molecular orbitals begins with the interaction of atomic orbitals (AOs), which are based on the fundamental principles of quantum mechanics. AOs represent the probability distribution of an electron around an atom and are characterized by distinct shapes and energy levels. When two atoms approach each other, their orbitals begin to interact, and this interaction is what can lead either to the formation of a molecular bond or to a repulsive interaction that prevents bond formation.

These interactions result in the formation of molecular orbitals, with certain rules governing the outcome. One key rule is the conservation of orbitals—when two atomic orbitals combine, they must create two molecular orbitals: one bonding and one antibonding. Another rule is that the combination of orbitals must preserve the symmetry of the participating atoms' orbitals. What's fascinating here is that the resulting molecular orbitals extend over multiple atoms, unlike atomic orbitals which are concentrated around a single nucleus, and this property grants molecules their unique characteristics.
Molecular Orbital Theory
Molecular Orbital (MO) Theory provides an advanced framework for understanding chemical bonding. According to MO theory, electrons in a molecule are not restricted to individual atoms but are distributed in orbitals that can extend over the entire molecule. This theory contrasts with the Valence Bond Theory, which restricts electron pairs to specific atoms or shared between atoms in covalent bonds.

MO theory can predict magnetic properties, the existence of molecules that can't be explained by other theories, and the detailed electronic structure that leads to an understanding of a molecule's reactivity and properties. The theory succeeds particularly well in explaining the bonding in diatomic molecules, providing insights into why oxygen is paramagnetic and why the bonding in homonuclear diatomic molecules like N2 is so strong. MO theory is a keystone for students of chemistry and essential for piecing together the often complex puzzle of molecular structure and behavior.

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Most popular questions from this chapter

Which of the following statements concerning \(\mathrm{SO}_{2}\) is(are) true? a. The central sulfur atom is \(s p^{2}\) hybridized. b. One of the sulfur-oxygen bonds is longer than the other(s). c. The bond angles about the central sulfur atom are about 120 degrees. d. There are two \(\sigma\) bonds in \(\mathrm{SO}_{2}\). e. There are no resonance structures for \(\mathrm{SO}_{2}\).

Bond energy has been defined in the text as the amount of energy required to break a chemical bond, so we have come to think of the addition of energy as breaking bonds. However, in some cases the addition of energy can cause the formation of bonds. For example, in a sample of helium gas subjected to a high-energy source, some \(\mathrm{He}_{2}\) molecules exist momentarily and then dissociate. Use MO theory (and diagrams) to explain why \(\mathrm{He}_{2}\) molecules can come to exist and why they dissociate.

Show how two \(2 p\) atomic orbitals can combine to form a \(\sigma\) or a \(\pi\) molecular orbital.

In terms of the molecular orbital model, which species in each of the following two pairs will most likely be the one to gain an electron? Explain. a. CN or \(\mathrm{NO}\) b. \(\mathrm{O}_{2}^{2+}\) or \(\mathrm{N}_{2}^{2+}\)

The diatomic molecule OH exists in the gas phase. The bond length and bond energy have been measured to be \(97.06 \mathrm{pm}\) and \(424.7 \mathrm{~kJ} / \mathrm{mol}\), respectively. Assume that the \(\mathrm{OH}\) molecule is analogous to the HF molecule discussed in the chapter and that molecular orbitals result from the overlap of a lowerenergy \(p_{z}\) orbital from oxygen with the higher-energy \(1 s\) orbital of hydrogen (the \(\mathrm{O}-\mathrm{H}\) bond lies along the \(z\) -axis). a. Which of the two molecular orbitals will have the greater hydrogen \(1 s\) character? b. Can the \(2 p_{x}\) orbital of oxygen form molecular orbitals with the \(1 s\) orbital of hydrogen? Explain. c. Knowing that only the \(2 p\) orbitals of oxygen will interact significantly with the \(1 s\) orbital of hydrogen, complete the molecular orbital energy- level diagram for \(\mathrm{OH}\). Place the correct number of electrons in the energy levels. d. Estimate the bond order for OH. e. Predict whether the bond order of \(\mathrm{OH}^{+}\) will be greater than, less than, or the same as that of OH. Explain.

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