Chapter 9: Problem 48
Using the molecular orbital model to describe the bonding in \(\mathrm{F}_{2}{ }^{+}, \mathrm{F}_{2}\), and \(\mathrm{F}_{2}^{-}\), predict the bond orders and the relative bond lengths for these three species. How many unpaired electrons are present in each species?
Short Answer
Expert verified
The bond order, unpaired electrons, and relative bond lengths for the three fluorine species are:
- \(F_2\): Bond order 1, 0 unpaired electrons, and longer bond length than \(F_2^-\).
- \(F_2^+\): Bond order 0.5, 1 unpaired electron, and longest bond length.
- \(F_2^-\): Bond order 1.5, 1 unpaired electron, and shortest bond length.
Step by step solution
01
Understanding the Molecular Orbital Model
The molecular orbital model represents the electrons in molecules as occupying a set of molecular orbitals, created from the interaction of individual atomic orbitals from each atom. In the case of these fluorine species, we are considering the bonding between two F atoms.
The molecular orbitals formed by overlapping atomic orbitals in F2, F2+, and F2- are σ(2s), σ(2s)*, σ(2p), σ(2p)*, π(2p), π(2p)*, and their corresponding antibonding orbitals. The σ(2s) and σ(2s)* orbitals are derived from the overlap of the 2s orbitals of each of the individual F atoms, and the σ(2p) and σ(2p)* orbitals arise from the interaction between the 2p atomic orbitals.
02
Filling the Molecular Orbitals
Each fluorine atom has 9 electrons, 2 in the 1s orbital, 2 in the 2s orbital, and 5 in the 2p orbitals. To determine the electron configuration of the species F2, F2+ and F2-, we need to fill the molecular orbitals in order of increasing energy, following Hund's rule and Pauli's exclusion principle. Look at each species:
- \(F_2\): Two F atoms are the 18 electrons to fill the molecular orbitals.
- \(F_2^+\): The F2+ species have only 17 electrons (1 electron has been removed).
- \(F_2^-\): The F2- species have 19 electrons (1 electron has been added).
03
Calculating Bond Order and Counting Unpaired Electrons
To predict bond orders and count unpaired electrons, we will use the bond order formula:
Bond order = (Number of electrons in bonding orbitals - Number of electrons in antibonding orbitals) / 2
We fill the molecular orbitals for each species using the number of electrons:
- \(F_2\): σ(2s)²σ(2s)*²σ(2p)²π(2p)⁴π(2p)*²
- Bond order: (8-6)/2 = 1
- Unpaired electrons: 0
- \(F_2^+\): σ(2s)²σ(2s)*²σ(2p)²π(2p)⁴π(2p)*¹
- Bond order: (7-6)/2 = 0.5
- Unpaired electrons: 1
- \(F_2^-\): σ(2s)²σ(2s)*²σ(2p)²π(2p)⁴π(2p)*³
- Bond order: (9-6)/2 = 1.5
- Unpaired electrons: 1
04
Predicting Relative Bond Lengths
The bond order is directly proportional to bond strength and inversely proportional to bond length. Therefore:
- \(F_2\) (bond order 1) has a longer bond length than \(F_2^-\) (bond order 1.5).
- \(F_2^+\) (bond order 0.5) has the longest bond length among the three species.
#Summary#
The bond order, unpaired electrons, and relative bond lengths for the three species are:
- F2: Bond order 1, 0 unpaired electrons, and longer bond length than F2-.
- F2+: Bond order 0.5, 1 unpaired electron, and longest bond length.
- F2-: Bond order 1.5, 1 unpaired electron, and shortest bond length.
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Key Concepts
These are the key concepts you need to understand to accurately answer the question.
Bond Order
Bond order represents the number of chemical bonds between a pair of atoms, providing insight into the stability and strength of the bond. In the molecular orbital model, bond order is calculated by taking the difference between the number of electrons in bonding molecular orbitals and those in antibonding molecular orbitals, then dividing by two. The formula is:
\[ \text{Bond order} = \frac{(\text{Number of electrons in bonding orbitals} - \text{Number of electrons in antibonding orbitals})}{2} \]. influences molecular stability and determines the length of the bond. A higher bond order indicates a stronger and shorter bond, while a lower bond order suggests a weaker and longer bond. For example, a single bond has a bond order of 1, a double bond, 2, and a triple bond, 3. In the fluorine molecules from the exercise:
\[ \text{Bond order} = \frac{(\text{Number of electrons in bonding orbitals} - \text{Number of electrons in antibonding orbitals})}{2} \].
- \(F_2\) has a bond order of 1, representing a single bond.
- \(F_2^{+}\) has a bond order of 0.5, indicating a bond weaker than a single bond.
- \(F_2^{-}\) has a bond order of 1.5, suggesting a bond stronger than a single bond but weaker than a double bond.
Electron Configuration
Electron configuration describes the distribution of electrons among the various atomic or molecular orbitals. For atoms, it follows a specific order filling subshells such as 1s, 2s, 2p, etc. In molecular systems, electrons occupy molecular orbitals, which arise from the combination of atomic orbitals. When several atomic orbitals combine, they form the same number of molecular orbitals, with some being of lower energy (bonding) and some of higher energy (antibonding).Following Hund's rule and the Pauli exclusion principle, each electron is placed into the lowest energy orbital available, with electrons in the same orbital spinning in opposite directions to comply with Pauli's rule. In the exercise, the electron configurations for \(F_2\), \(F_2^{+}\), and \(F_2^{-}\) are filled out according to their respective number of electrons with the specific aim to minimize energy. Each species has a distinct configuration affecting the bond order:
- \(F_2\) has a full set of electrons in both bonding and antibonding orbitals leading to a bond order of 1.
- \(F_2^{+}\) has one less electron, causing a decrease in bond order to 0.5.
- \(F_2^{-}\) has an additional electron, which increases the bond order to 1.5.
Molecular Orbitals
Molecular orbitals (MOs) form the foundation of the molecular orbital theory, which explains the electron structure of molecules. MOs result from the linear combination of atomic orbitals (AOs), and they extend over the entire molecule. According to this theory, electrons in a molecule are not confined to individual AOs of atoms but are instead delocalized over MOs that belong to the molecule as a whole.