Chapter 9: Problem 55
Show how two \(2 p\) atomic orbitals can combine to form a \(\sigma\) or a \(\pi\) molecular orbital.
Chapter 9: Problem 55
Show how two \(2 p\) atomic orbitals can combine to form a \(\sigma\) or a \(\pi\) molecular orbital.
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Get started for freeValues of measured bond energies may vary greatly depending on the molecule studied. Consider the following reactions: $$ \begin{array}{cc} \mathrm{NCl}_{3}(g) \longrightarrow \mathrm{NCl}_{2}(g)+\mathrm{Cl}(g) & \Delta H=375 \mathrm{~kJ} / \mathrm{mol} \\ \mathrm{ONCl}(g) \longrightarrow \mathrm{NO}(g)+\mathrm{Cl}(g) & \Delta H=158 \mathrm{~kJ} / \mathrm{mol} \end{array} $$ Rationalize the difference in the values of \(\Delta H\) for these reactions, even though each reaction appears to involve only the breaking of one \(\mathrm{N}-\mathrm{Cl}\) bond. (Hint: Consider the bond order of the NO bond in ONCl and in NO.)
Draw the Lewis structures for \(\mathrm{TeCl}_{4}, \mathrm{ICl}_{5}, \mathrm{PCl}_{5}, \mathrm{KrCl}_{4}\), and \(\mathrm{XeCl}_{2}\). Which of the compounds exhibit at least one bond angle that is approximately 120 degrees? Which of the compounds exhibit \(d^{2} s p^{3}\) hybridization? Which of the compounds have a square planar molecular structure? Which of the compounds are polar?
Why does the molecular orbital model do a better job in explaining the bonding in \(\mathrm{NO}^{-}\) and \(\mathrm{NO}\) than the hybrid orbital model?
Use the MO model to determine which of the following has the smallest ionization energy: \(\mathrm{N}_{2}, \mathrm{O}_{2}, \mathrm{~N}_{2}{ }^{2-}, \mathrm{N}_{2}^{-}, \mathrm{O}_{2}^{+} .\) EX- plain your answer.
Draw the Lewis structure for HCN. Indicate the hybrid orbitals, and draw a picture showing all the bonds between the atoms, labeling each bond as \(\sigma\) or \(\pi\).
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