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Chapter 13: Problem 7

Without attempting to draw a Lewis structure, calculate the total number of valence electrons in each of these molecules: a) \(\mathrm{H}_{2} \mathrm{CO}\) b) \(\mathrm{N}_{2}\) c) \(\mathrm{Cl}_{2}\)

Short Answer

Expert verified
\(\mathrm{H}_{2} \mathrm{CO}\) has 12 total valence electrons, \(\mathrm{N}_{2}\) has 10 total valence electrons, \(\mathrm{Cl}_{2}\) has 14 total valence electrons.

Step by step solution

01

Determine the number of valence electrons for each atom

For \(\mathrm{H}_{2} \mathrm{CO}\), Hydrogen (H) has 1 valence electron, Oxygen (O) has 6, and Carbon (C) has 4 valence electrons. For \(\mathrm{N}_{2}\), Nitrogen (N) has 5 valence electrons. For \(\mathrm{Cl}_{2}\), Chlorine (Cl) has 7 valence electrons.
02

Multiply each atom's valence electrons by the subscript

For \(\mathrm{H}_{2} \mathrm{CO}\), there are 2 Hydrogen atoms, and 1 Oxygen and 1 Carbon atom. So the total is \(2*1 + 1*6 + 1*4 = 12\) valence electrons. For \(\mathrm{N}_{2}\), there are 2 Nitrogen atoms, so the total is \(2*5 = 10\) valence electrons. For \(\mathrm{Cl}_{2}\), there are 2 Chlorine atoms, so the total is \(2*7 = 14\) valence electrons.
03

Summarize the total valence electrons for each molecule

\(\mathrm{H}_{2} \mathrm{CO}\) has 12 total valence electrons. \(\mathrm{N}_{2}\) has 10 total valence electrons. \(\mathrm{Cl}_{2}\) has 14 total valence electrons.

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Most popular questions from this chapter

For \(\mathrm{N}_{2}\), is the sum of the bonding electrons and nonbonding electrons around each nitrogen atom consistent with the Lewis model?

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