How were the number of electrons in the possible Lewis structures of \(\mathrm{CO}_{2}\) calculated?

Short Answer

Expert verified
In the Lewis structure of \(\mathrm{CO}_{2}\), there are 16 electrons in total which are distributed accordingly to satisfy the Octet Rule for all atoms - Carbon (C) and Oxygen (O). This number was calculated by adding up the valence electrons: 4 from Carbon and 6 from each Oxygen atom.

Step by step solution

01

Identifying the total number of valence electrons

First, calculate the total number of valence electrons in the given molecule, \(\mathrm{CO}_{2}\). Know that Carbon (C) has 4 valence electrons and Oxygen (O) has 6. But since there are two Oxygen atoms in the molecule, multiply 6 by 2. So, the total number of valence electrons is 4 (from Carbon) + 12 (from 2 Oxygen atoms) = 16.
02

Distributing the electrons

In a Lewis structure, start placing the electrons from the outside atoms. First, satisfy the Octet Rule for the Oxygen atoms by placing 8 electrons on each (6 are required for an octet, but 2 have already been accounted for by the bonding shared with Carbon). You've used 16 electrons up to this point.
03

Verifying the Octet Rule

Check the Octet Rule for all atoms. Carbon should also have 8 electrons (4 its own, and 4 from the bonds with Oxygen). Both Oxygen atoms already meet the Octet Rule, as they each have 8 electrons. Therefore, the Lewis structure is correct.

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