Chapter 21: Problem 3
For \(\mathrm{HF}\), why is \(\delta_{\mathrm{F}}=-\delta_{\mathrm{H}}\) ?
Short Answer
Expert verified
In a dipole moment, charges in the bond are distributed according to the electronegativity of the atoms. The arrow of the dipole moment points from the positively charged atom (with lower electronegativity, Hydrogen here) towards the negatively charged atom (with higher electronegativity, Fluorine here). Hence, Fluorine has negative 'delta' and Hydrogen has positive 'delta', so \(\delta_{F} = -\delta_{H}\).