For \(\mathrm{HF}\), why is \(\delta_{\mathrm{F}}=-\delta_{\mathrm{H}}\) ?

Short Answer

Expert verified
In a dipole moment, charges in the bond are distributed according to the electronegativity of the atoms. The arrow of the dipole moment points from the positively charged atom (with lower electronegativity, Hydrogen here) towards the negatively charged atom (with higher electronegativity, Fluorine here). Hence, Fluorine has negative 'delta' and Hydrogen has positive 'delta', so \(\delta_{F} = -\delta_{H}\).

Step by step solution

01

Understand the concept of dipole moment

In a molecule, the dipole moment measures the charge separation in a system of charges which is equivalent to a dipole. It is given by the product of a charge (which is partial when the bond is covalent) and the distance between the charges. In a diatomic molecule, the dipole moment is directed from the less electronegative atom to the more electronegative one.
02

Study the Fluorine-Hydrogen bond

In a Fluorine-Hydrogen bond, Fluorine is more electronegative than Hydrogen which means it will more strongly attract the bonding electron pair. Therefore, Fluorine will have a partial negative charge and Hydrogen will have a partial positive charge. The dipole moment will point from Hydrogen to Fluorine.
03

Define 'delta'

In this context, 'delta' refers to the partial charge on the atoms in a polar covalent bond. Its value depends on the electronegativity difference between the two atoms. 'delta' is positive for the less electronegative atom (Hydrogen) and negative for the more electronegative atom (Fluorine). This is why \(\delta_{F} = -\delta_{H}\).

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