Consider the ionic compounds \(\mathrm{MgO}\) and \(\mathrm{MgS}\) : a) In which compound is the Coulombic force of attraction greater? b) \(\mathrm{MgO}\) has a melting point of \(2852^{\circ} \mathrm{C}\). Which of these would you predict is the melting point of \(\mathrm{MgS}:\) about \(2000{ }^{\circ} \mathrm{C}\), about \(2850{ }^{\circ} \mathrm{C}\), about \(4000{ }^{\circ} \mathrm{C}\) ? Explain your reasoning.

Short Answer

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a) The Coulombic force of attraction is greater in MgO. b) The melting point of MgS would be predicted to be around 2000 degree Celsius.

Step by step solution

01

Comparison of Coulombic force

The Coulombic force of attraction in ionic compounds can be calculated using the formula \( F = \frac{q1*q2}{r^2} \), where q1& q2 are the charges on the ions and r is the radius/distance between the ions. Consider the compounds MgO and MgS. In MgO, Mg has a charge of +2 and O has a charge of -2. In MgS, Mg has a charge of +2 and S has a charge of -2. Since both compounds have the same magnitude of charges, their Coulombic forces are determined by the distances between the ions. The oxygen ion is smaller than the sulfide ion, so the distance between ions in MgO is smaller, which means that the Coulombic force in MgO is greater.
02

Predicting the melting point

The stronger the Coulombic force of attraction in a compound (MgO in this case), the higher its melting point. Given that MgO has a higher Coulombic force and a melting point of 2852 degree Celsius, MgS, with a relatively lower Coulombic force, should have a lower melting point. Among the given options, the temperature lower than 2852 degree Celsius is 2000 degree Celsius, so one would expect the melting point of MgS to be around this value.

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Melting Point Prediction
Understanding the melting point of ionic compounds like MgO and MgS is a fascinating exploration into the world of chemistry. The melting point is the temperature at which a substance changes from a solid to a liquid, and it's a crucial property that can, for instance, affect the material's application in various industries. In the case of ionic compounds, the melting point can be estimated by considering the strength of attractions between ions, also known as the Coulombic force of attraction.

In the exercise, MgO's known high melting point of 2852°C sets a benchmark. By comparing the Coulombic force in MgO and MgS, we infer that the stronger this force, the greater the energy needed to overcome these attractions, which in turn suggests a higher melting point. Given MgO's stronger Coulombic force due to its smaller ionic radii and therefore shorter distance between ions, it has a significantly high melting point. Consequently, for MgS, with weaker Coulombic forces, we predict a lower melting point, likely around the given option of 2000°C.

This prediction aligns with the general rule: ionic compounds with stronger ionic bonds tend to have higher melting points. Thus, understanding the impact of ionic interactions on melting points enables us to predict the physical properties of unknown or less familiar compounds.
Ionic Bond Strength
The essence of ionic bond strength in compounds like MgO and MgS cannot be overstated when it comes to determining their physical characteristics. An ionic bond is the electrostatic force of attraction between positively (cation) and negatively (anion) charged ions. The strength of these bonds directly influences a compound's melting point, hardness, and solubility, among other properties.

To gauge the bond strength, one can look at the charge magnitude of the ions and the distance between them. In the context of the exercise, both MgO and MgS have ions with a charge of +2 and -2. However, because of the smaller ionic radius of oxygen compared to sulfur, the ions in MgO are closer together. This reduced distance amplifies the attraction—illustrating Coulomb's law that force increases as distance decreases—and consequently, the bond strength. Thus, MgO possesses a stronger ionic bond than MgS, which directly correlates to its higher melting point, reinforcing the link between bond strength and thermal stability.

By delving deeply into ionic bond strength, students are better equipped to rationalize why certain ionic compounds exhibit different physical attributes based on the nature of their ionic bonds, enhancing their comprehension of ionic structures and their implications.
Comparing Ionic Radii
The size of ions plays a key role in the behavior of ionic compounds, and comparing ionic radii is fundamental in understanding properties like bond strength and melting points. Ionic radius is the distance from the nucleus to the outermost electrons of an ion. When contrasting ions like O²⁻ and S²⁻, the size difference is attributed to the number of electron shells, with sulfur having more, making the S²⁻ ion larger than the O²⁻ ion.

In our exercise, this comparison is crucial because the larger ionic radius of S²⁻ in MgS means the ions are further apart compared to those in MgO, resulting in weaker Coulombic attractions and a lower melting point for MgS. Conversely, the smaller O²⁻ ions of MgO are closer to the Mg²⁺ ions, leading to a stronger Coulombic force, hence a higher melting point.

By scrutinizing ionic radii, we provide a more in-depth explanation of the step-by-step solution and improve comprehension of why MgO, with its smaller ionic radius and tighter ion packing, has more robust bonds and a relatively higher melting point than MgS. This knowledge empowers students not just to predict melting points, but also to draw conclusions about other properties that are influenced by the size of ions, such as the solubility and density of ionic compounds.

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