Verify that when \(10.0 \mathrm{~g}\) of sodium sulfate dissolves in water: a) there are \(7.04 \times 10^{-2}\) moles of sodium sulfate in the water. b) there are \(7.04 \times 10^{-2}\) moles of sulfate in the water. c) there are \(14.1 \times 10^{-2}\) moles of sodium in the water.

Short Answer

Expert verified
The given data in the problem set is correct. When 10.0 g of sodium sulfate dissolves in water, there are indeed \(7.04 \times 10^{-2}\) moles of sodium sulfate, \(7.04 \times 10^{-2}\) moles of sulfate and approximately \(14.1 \times 10^{-2}\) moles of sodium in the water.

Step by step solution

01

Calculation of Moles of Sodium Sulfate

We need to calculate the moles of sodium sulfate which is given by the formula: \( \text{Moles} = \frac{\text{mass}}{\text{molar mass}} \) where the molar mass of sodium sulfate \((Na_2SO_4)\) is approximately 142 g/mol. So, moles of sodium sulfate = \(\frac{10.0 g}{142 g/mol} = 7.04 \times 10^{-2} mol\). Verify that it matches with the given amount in the problem.
02

Calculation of Moles of Sulfate

When sodium sulfate dissolves in water, it dissociates into 2 sodium ions and 1 sulfate ion. So, the number of moles of sulfate ions is the same as the number of moles of sodium sulfate, which equals \(7.04 \times 10^{-2} mol\). Check if this value matches with the given value in the problem.
03

Calculation of Moles of Sodium

Given that every mole of sodium sulfate dissociates into 2 moles of sodium ions, the number of moles of sodium ions is double. So, moles of sodium = \(2 \times 7.04 \times 10^{-2} mol = 14.08 \times 10^{-2} mol\). Check if this value matches with the given value in the problem, accounting for rounding errors.

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