The value of the ionization energy of He given in Table 1 is described as being consistent with two electrons in a "shell" approximately the same distance from the nucleus as the one electron in H. Use the Coulombic Potential Energy equation, \(V=\frac{\mathrm{kq}_{1} \mathrm{q}_{2}}{\mathrm{~d}}\) to explain how this conclusion can be reached. Hint: recall the relationship between \(V\) and \(\mathrm{IE}_{1}\).

Short Answer

Expert verified
The ionization energy of Helium is twice that of Hydrogen, as it has two electrons approximately at the same distance from the nucleus as Hydrogen's one electron. This complies with the Coulombic Potential Energy equation, confirming the assertion from the table.

Step by step solution

01

Identifying Variables in Ionization Energy Context

Initially, the concept of ionization energy needs to be identified. Ionization energy (\(IE_1\)) is the energy required to remove an electron from an atom or an ion. In this case, the ionization energy of He (Helium) will be twice that of H (Hydrogen) because He has two electrons compared to one electron in H. This is due to the analogy that both electrons in He are at the same distance from the nucleus as the one electron in H.
02

Applying Coulombic Potential Energy Equation

Now, the Coulombic potential energy equation, \(V = \frac{kq_1q_2}{d}\), where \(V\) is potential energy, \(q_1\) and \(q_2\) are charges (in this case, of electrons and nucleus), \(k\) is Coulomb's constant, and \(d\) is the distance between the charges, needs to be applied. Since for both H and He the distance from the nucleus is the same and charges are also similar, the potential energy for both will be the same. The charges here would be the charge of electron and charge of nucleus.
03

Connecting Ionization Energy and Potential Energy

Understanding that the potential energy (\(V\)) is related to the ionization energy (\(IE_1\)) will help draw a conclusion. A lower potential energy implies a higher ionization energy as it would take more energy to remove the electron from the atom. Since both H and He have the same potential energy as per the Coulombic equation, He should theoretically have twice the ionization energy of H because it has twice the electrons of H.

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