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Chapter 41: Problem 12

Is \(\mathrm{Mg}(\mathrm{OH})_{2}\) considered to be a soluble or insoluble compound? Explain your answer.

Short Answer

Expert verified
\(\mathrm{Mg(OH)}_{2}\) is considered an insoluble compound because it does not meet the conditions required for a hydroxide to be soluble according to the solubility table.

Step by step solution

01

Understanding Solubility

Solubility is a property referring to the ability of a given substance, the solute, to dissolve in a solvent. It is measured in terms of the maximum amount of solute that can be dissolved in a solvent at equilibrium. The solubility of a substance fundamentally depends on the physical and chemical properties of the solute and solvent as well as on temperature, pressure, and the pH of the solution. The solubility of a substance in a particular solvent is generally expressed as the number of parts of solute that will dissolve in 100 parts of solvent at a given temperature.
02

Referencing A Solubility Table

To find out whether \(\mathrm{Mg(OH)}_{2}\) is soluble or insoluble, we can check its solubility in a solubility table. Generally, majority of the hydroxides (\(OH^-)\) are insoluble. There are exceptions, including compounds of Group 1 elements (Lithium, Sodium, Potassium, Rubidium, Cesium) and ammonium ion (\(NH_4^+\)) are soluble. Some transition metals and heavy Alkali earth metals form soluble hydroxides as temperature increases. But Magnesium Hydroxide \(\mathrm{Mg(OH)}_{2}\) does not fall into this exceptions and is considered to be an insoluble compound when it comes to majority of the commonly used solvents including water.
03

Conclusion

From the solubility rules, we find that Magnesium Hydroxide \(\mathrm{Mg(OH)}_{2}\) is considered to be an insoluble compound. This is because it does not meet any of the conditions required for hydroxides to be soluble.

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