The acids in Table 2 are divided into two groups: those with \(K_{\mathrm{a}}>1\) and those with \(\mathrm{K}_{\mathrm{a}}<1\). Describe each of these two groups in terms of percent dissociation.

Short Answer

Expert verified
Acids with a Ka greater than 1 are strong acids and dissociate almost completely in solution, leading to a percent dissociation near 100%. In contrast, acids with a Ka less than 1 are weak acids and dissociate to a lesser extent, resulting in a lower percent dissociation.

Step by step solution

01

Understand Ka and Percent Dissociation

The acid dissociation constant, Ka, is a measure of the strength of an acid in solution. Larger Ka values correspond to stronger acids. Percent dissociation is a measure of the degree to which the acid molecules separate or dissociate into their ions in solution. The higher the percent dissociation, the more the acid has dissociated into its ions.
02

Describe Acids with Ka > 1

Acids with Ka greater than 1 are strong acids. This means that they dissociate almost completely in solution. Therefore, these types of acids have a percent dissociation that approaches 100%.
03

Describe Acids with Ka < 1

On the other hand, acids with Ka less than 1 are weak acids. They dissociate to a lesser extent in solution, thus, they have a percent dissociation much less than 100%.

Unlock Step-by-Step Solutions & Ace Your Exams!

  • Full Textbook Solutions

    Get detailed explanations and key concepts

  • Unlimited Al creation

    Al flashcards, explanations, exams and more...

  • Ads-free access

    To over 500 millions flashcards

  • Money-back guarantee

    We refund you if you fail your exam.

Over 30 million students worldwide already upgrade their learning with Vaia!

One App. One Place for Learning.

All the tools & learning materials you need for study success - in one app.

Get started for free

Most popular questions from this chapter

See all solutions

Recommended explanations on Chemistry Textbooks

View all explanations

What do you think about this solution?

We value your feedback to improve our textbook solutions.

Study anywhere. Anytime. Across all devices.

Sign-up for free