Is \(\Delta S\) for the following process positive or negative? Why? \(\mathrm{C}_{4} \mathrm{H}_{8}(\mathrm{~g} ; 298 \mathrm{~K} ; 1 \mathrm{~atm}) \rightleftharpoons \mathrm{C}_{4} \mathrm{H}_{8}(\mathrm{~g} ; 298 \mathrm{~K} ; 0.5 \mathrm{~atm})\)

Short Answer

Expert verified
\(\Delta S\) for the given process is positive because the system is moving from a state of higher pressure to lower pressure, which increases the randomness or disorder of the gas molecules.

Step by step solution

01

Identify the initial and final states

Identify the initial and final states of the system. Here, the initial state is \(C_4H_8(g)\) at 298 K and 1 atm, and the final state is \(C_4H_8(g)\) at 298 K and 0.5 atm.
02

Compare the pressure conditions

Compare the pressure of the initial and final states. The initial state has higher pressure (1 atm) compared to the final state (0.5 atm).
03

Analyze the entropy change

As the system moves from a state of higher pressure to lower pressure, the disorder or randomness of the gas molecules increases because they have more space to move around. Therefore, the entropy change, \(\Delta S\), is positive.

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