\begin{aligned} &\text { Complete the following table: }\\\ &\begin{array}{|c|l|l|} \hline \text { Element } & n \text { for the valence shell } & \text { IE }_{1}(\mathrm{MJ} / \mathrm{mole}) \\ \hline \mathrm{N} & & \\ \hline \mathrm{Ar} & & \\ \hline \end{array} \end{aligned}

Short Answer

Expert verified
The completed table will be: \[\begin{array}{|c|c|c|} \hline \text{Element} & n \text{for the valence shell} & IE_1 (MJ/mol) \\ \hline N & 2 & 14.5341 \\ Ar & 3 & 15.7596 \\ \hline \end{array}\]

Step by step solution

01

Determine the valence shell for Nitrogen (N)

To find the valence shell for Nitrogen (N), we can take a look at the periodic table. Nitrogen has an atomic number of 7, which means it has 7 electrons. The electron configuration for Nitrogen is \(1s^2 2s^2 2p^3\), the highest value of principal quantum number 'n' is 2. So, the valence shell for Nitrogen \(n = 2\).
02

Determine the 1st Ionization Energy for Nitrogen (N)

The first ionization energy for any element is usually provided in tables or can be found in a chemistry handbook or online. According to various sources, the first ionization energy for Nitrogen is approximately \(14.5341 \, MJ/mol\).
03

Determine the valence shell for Argon (Ar)

Argon (Ar) is in the 18th group of the Periodic Table. Its electron configuration ends in 3p6. So, the valence shell for Argon \(n = 3\).
04

Determine the 1st Ionization Energy for Argon (Ar)

Similar to Nitrogen, the first ionization energy for Argon can be found in ionization energy tables or online. The first ionization energy for Argon is approximately \(15.7596 \, MJ/mol\).

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