Chapter 10: Problem 10
In the photoelectron spectrum of Sc, the peak at \(0.63 \mathrm{MJ} / \mathrm{mole}\) is assigned to the \(4 s\) subshell. Why is the peak at \(0.77 \mathrm{MJ} / \mathrm{mole}\) in the \(\mathrm{Sc}\) spectrum assigned as a third subshell of \(n=3\) (named \(3 d\) ) as opposed to being a second subshell of \(n\) \(=4\) (that is, \(4 p)\) ?
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Key Concepts
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