Chapter 24: Problem 2

Individually answer the two parts below. Then compare your answer with the other members of your team, come to consensus answers, and add your team's responses to Table 1 . a) Determine the \(\Delta \mathrm{EN}\) value and the \(\overline{\mathrm{EN}}\) value for \(\mathrm{HI}\). b) Determine the \(\Delta \mathrm{EN}\) value and the \(\overline{\mathrm{EN}}\) value for GaAs.

Short Answer

Expert verified

The \(\Delta EN\) for HI is 0.4 and the \(\overline{EN}\) is 2.3. The \(\Delta EN\) for GaAs is 0.58 and the \(\overline{EN}\) is 1.89.

Step by step solution

Determine Electronegativity value of elements in HI

From the periodic table, we know the electronegativity of Hydrogen (H) is 2.1 and that of Iodine (I) is 2.5.

Calculate \(\Delta \mathrm{EN}\) and \(\overline{\mathrm{EN}}\) for HI

The Electronegativity difference, \(\Delta \mathrm{EN}\) can be found by subtracting the two electronegativity values, \(|\) 2.1 - 2.5 \(|\) which equals 0.4. Average Electronegativity, \(\overline{\mathrm{EN}}\), is the average of the two electronegativity values, \(\frac{2.1 + 2.5}{2}\) equals 2.3.

Determine Electronegativity value of elements in GaAs

From the periodic table, we know the electronegativity of Gallium (Ga) is 1.6 and that of Arsenic (As) is 2.18.

Calculate \(\Delta \mathrm{EN}\) and \(\overline{\mathrm{EN}}\) for GaAs

The Electronegativity difference, \(\Delta \mathrm{EN}\) can be found by subtracting the two electronegativity values, \(|\) 1.6 - 2.18 \(|\) which equals 0.58. Average Electronegativity, \(\overline{\mathrm{EN}}\), is the average of the two electronegativity values, \(\frac{1.6 + 2.18}{2}\) equals 1.89.

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Short Answer

Step by step solution

Determine Electronegativity value of elements in HI

Calculate \(\Delta \mathrm{EN}\) and \(\overline{\mathrm{EN}}\) for HI

Determine Electronegativity value of elements in GaAs

Calculate \(\Delta \mathrm{EN}\) and \(\overline{\mathrm{EN}}\) for GaAs

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