Provide an expression relating \(K_{\mathrm{w}}\) to \(K_{\mathrm{a}}\) and \(K_{\mathrm{b}}\) of a conjugate acid-base pair.

Short Answer

Expert verified
The relationship between the ion product of water (\(K_{w}\)), the acid dissociation constant (\(K_{a}\)), and the base dissociation constant (\(K_{b}\)) for a conjugate acid-base pair is given by: \(K_{w} = K_{a} * K_{b}\)

Step by step solution

01

Understanding Conjugate Acid-Base Pairs

In an acid/base reaction, when the acid donates a proton, the remaining portion becomes its conjugate base. Similarly, when a base accepts a proton, it becomes a conjugate acid. For a given acid and its conjugate base or a given base and its conjugate acid, \(K_{a}\) expresses the degree to which the acid dissociates to form its conjugate base and a free proton (H+), whereas \(K_{b}\) expresses the degree to which the base dissociates to form its conjugate acid and a free hydroxide ion (OH−).
02

Understanding Ion Product of Water (\(K_{w}\))

The product of the concentrations of the hydrogen ions (H+) and hydroxide ions (OH−) in water at a given temperature is known as the ion product of water (\(K_{w}\)). At 25°C, \(K_{w}\) is 1.0*10^-14.
03

Relating \(K_{w}\), \(K_{a}\) and \(K_{b}\)

Given that acid and base dissociation processes produce hydrogen and hydroxide ions, we can relate \(K_{w}\), \(K_{a}\), and \(K_{b}\) as follows: \(K_{w} = K_{a} * K_{b}\). This equation states that for a given acidic solution at 25°C, the product of \(K_{a}\) for the acid and \(K_{b}\) for its conjugate base equals the ion product of water (\(10^{-14}\)).

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