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Chapter 53: Problem 9

Eor a chemical reaction with \(K>1\), is \(\Delta G^{\circ}\) positive or negative?

Short Answer

Expert verified
The \(\Delta G^{\circ}\) for a chemical reaction with \(K>1\) is negative.

Step by step solution

01

Establish the Relationship

Understand the relation between equilibrium constant, K, and standard Gibbs free energy, \(\Delta G^{\circ}\), as given by the formula: \(\Delta G^{\circ} = -RT ln K\).
02

Analyze the Given Condition

Here we are given \(K>1\). In the natural logarithm, the ln of a number greater than 1 is positive. So ln(K) will be positive in this case.
03

Find the Sign of \(\Delta G^{\circ}\)

Insert the value of ln(K) in the formula. Since ln(K) is positive and \(\Delta G^{\circ} = -RT ln K\), hence \(\Delta G^{\circ}\) will be negative as it is the product of a positive and a negative term.

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Most popular questions from this chapter

For a chemical reaction with \(K<1\), is \(\Delta G^{\circ}\) positive or negative?

a) What values of \(\Delta H^{\circ}\) indicate that a reaction is energetically favorable? b) What values of \(\Delta S^{\circ}\) indicate that a reaction is entropically favorable?

If \(\Delta H^{\circ}=T \Delta S^{\circ}\), what is the value of \(\Delta G^{\circ}\) ? Predict the value of \(K\) in this case.
See all solutions

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