Chapter 15: Problem 68
The tabulated data show the rate constant of a reaction mea- sured at several different temperatures. Use an Arrhenius plot to determine the activation barrier and frequency factor for the reaction. $$ \begin{array}{cl} \text { Temperature (K) } & \text { Rate Constant (1/s) } \\ \hline 310 & 0.00434 \\ \hline 320 & 0.0140 \\ \hline 330 & 0.0421 \\ \hline 340 & 0.118 \\ \hline 350 & 0.316 \\ \hline \end{array} $$
Short Answer
Step by step solution
Understand the Arrhenius Equation
Prepare the Data for Plotting
Plot the Data on an Arrhenius Plot
Perform Linear Regression
Calculate the Activation Barrier and Frequency Factor
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Key Concepts
These are the key concepts you need to understand to accurately answer the question.
Activation Energy
In the context of an Arrhenius plot, which is a graph of ln(k) against 1/T, the activation energy can be derived from the slope of the line. A steeper negative slope indicates a higher activation energy, as more energy is required to increase the rate constant, k.