Suppose that the reaction \(\mathrm{A} \longrightarrow\) products is exothermic and has an activation barrier of \(75 \mathrm{~kJ} / \mathrm{mol} .\) Sketch an energy diagram showing the energy of the reaction as a function of the progress of the reaction. Draw a second energy curve showing the effect of a catalyst.

Short Answer

Expert verified
Sketch an energy diagram with reactants at a higher energy level than products. The first curve shows a peak 75 kJ/mol above the reactants, indicating the activation barrier. A second curve should be below the first, showing the lowered activation barrier due to the catalyst.

Step by step solution

01

Understand Exothermic Reactions

An exothermic reaction is one that releases heat, meaning the energy of the products is lower than the energy of the reactants. In an energy diagram, this is depicted by the products having a lower energy level compared to the reactants.
02

Drawing the Energy Diagram without a Catalyst

Begin by plotting the energy on the y-axis and the progress of the reaction on the x-axis. Mark the energy level of the reactants and label it 'Reactants'. Then, below this level, mark the energy level of the products and label it 'Products'. Draw a curve starting at the reactants' energy level, peaking at the point representing the activation energy (75 kJ/mol above the reactants), and then going down to the products' level.
03

Indicate Activation Energy

Label the peak of the curve as the 'Transition State' and draw a horizontal line from the reactants' level to the base of the peak. The vertical distance between the reactants and the peak represents the activation energy of 75 kJ/mol.
04

Drawing the Energy Diagram with a Catalyst

Draw a second curve on the same graph starting at the same reactants' level. The curve should peak lower than the original activation energy (75 kJ/mol) because the catalyst provides an alternative reaction pathway with a lower activation energy. The curve then goes down to the same products' level.
05

Label Catalyst Effect

Label the peak of the second curve as the 'Catalyzed Transition State'. The vertical distance between the reactants and this new peak represents the lower activation energy due to the catalyst. The presence of the catalyst is indicated by the decreased height of the energy barrier.

Unlock Step-by-Step Solutions & Ace Your Exams!

  • Full Textbook Solutions

    Get detailed explanations and key concepts

  • Unlimited Al creation

    Al flashcards, explanations, exams and more...

  • Ads-free access

    To over 500 millions flashcards

  • Money-back guarantee

    We refund you if you fail your exam.

Over 30 million students worldwide already upgrade their learning with Vaia!

Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Exothermic Reactions
Exothermic reactions are chemical processes that release energy into their surroundings, typically in the form of heat. These reactions result in a higher temperature of the surrounding environment. The classic indicators of an exothermic reaction include the warmth felt from an exothermic handwarmer or the heat produced when wood burns.

On an energy diagram, an exothermic reaction is represented by showing the products at a lower energy level than the reactants. This conveys that energy has been released to their surroundings as the reaction progresses. The energy difference between the reactants and products is called the heat of reaction or enthalpy change (\text{\(\tlDelta H\)}). For example, if a reaction starts with reactants at a certain energy level and ends with products at a lower level, the difference in these energy levels is the heat released during the reaction. In educational illustrations, the reactants are often placed at a higher point on the energy axis, sloping downward to the products, demonstrating the decrease in internal energy.
Activation Energy
Activation energy (\text{\(E_a\)}) is the minimum energy needed to initiate a chemical reaction. It can be envisioned as the 'energy barrier' that reactants must overcome for a reaction to occur. The concept of activation energy is crucial in understanding why some reactions occur spontaneously while others require input of energy, such as heat or light, to proceed.

An energy diagram visualizes this barrier as a peak that the reactants must climb in order to transform into products. Once the reactants have absorbed enough energy to reach the top of the peak, they undergo a transformation, passing through a high-energy, unstable transition state before releasing energy and becoming the lower-energy products in an exothermic reaction. The activation energy is depicted on the diagram as the height difference between the reactants' initial energy level and the peak of the curve.
Catalysts in Chemistry
Catalysts play a pivotal role in facilitating chemical reactions without being consumed in the process. In chemistry, a catalyst provides an alternative pathway for a reaction with a lower activation energy, thereby increasing the reaction rate. Catalysts are incredibly useful in industrial processes, biological systems, and laboratory reactions because they can dramatically reduce the energy requirements and expedite reactions that would otherwise be impractically slow or require high-energy conditions.

On an energy diagram, the effect of a catalyst is shown by comparing two curves: one without the catalyst and one with it. The latter curve peaks at a lower point, effectively lowering the 'hill' that the reactants must climb. While the start and end points remain the same—indicating that catalysts do not change the overall energy change of the reaction—the peak representing the transition state is lowered, illustrating the reduced activation energy required to reach the transition state thanks to the catalyst.
Transition State
The transition state, also known as the activated complex, represents a fleeting configuration of atoms at the point of highest energy during a chemical reaction. It is a state of maximum instability where old bonds are breaking, and new bonds are forming. The transition state cannot be isolated because of its short-lived existence, and it occupies a critical point on the energy diagram, marking the peak of the curve that represents the activation energy barrier.

In exothermic reactions, the energy diagram highlights the transition state as a peak which reactants must reach before descending towards the products. It signifies a decisive point in the reaction path where the potential energy is at its maximum and the fate of the reactants—to revert to the original state or to proceed to form products—is determined. This is a crucial concept in chemical kinetics, as the nature and energy of the transition state dictate the rate at which the reaction will proceed.

One App. One Place for Learning.

All the tools & learning materials you need for study success - in one app.

Get started for free

Most popular questions from this chapter

What are the four basic steps involved in heterogeneous catalysis?

Consider the reaction: $$ 2 \mathrm{~N}_{2} \mathrm{O}(g) \longrightarrow 2 \mathrm{~N}_{2}(g)+\mathrm{O}_{2}(g) $$ a. Express the rate of the reaction in terms of the change in concentration of each of the reactants and products. b. In the first \(15.0 \mathrm{~s}\) of the reaction, \(0.015 \mathrm{~mol}\) of \(\mathrm{O}_{2}\) is produced in a reaction vessel with a volume of \(0.500 \mathrm{~L}\). What is the average rate of the reaction during this time interval? c. Predict the rate of change in the concentration of \(\mathrm{N}_{2} \mathrm{O}\) during this time interval. In other words, what is \(\Delta\left[\mathrm{N}_{2} \mathrm{O}\right] / \Delta t ?\)

For the reaction \(2 \mathrm{~A}(g)+\mathrm{B}(g) \longrightarrow 3 \mathrm{C}(g),\) a. determine the expression for the rate of the reaction in terms of the change in concentration of each of the reactants and products. b. when \(A\) is decreasing at a rate of \(0.100 \mathrm{M} / \mathrm{s},\) how fast is \(\mathrm{B}\) decreasing? How fast is C increasing?

Three different reactions involve a single reactant converting to products. Reaction A has a half-life that is independent of the initial concentration of the reactant, reaction \(\mathrm{B}\) has a half-life that doubles when the initial concentration of the reactant doubles, and reaction \(\mathrm{C}\) has a half-life that doubles when the initial concentration of the reactant is halved. Which state- ment is most consistent with these observations? a. Reaction A is first order; reaction \(\mathrm{B}\) is second order; and reaction C is zero order. b. Reaction A is first order; reaction \(\mathrm{B}\) is zero order; and reaction C is zero order. c. Reaction A is zero order; reaction B is first order; and reaction C is second order. d. Reaction \(\mathrm{A}\) is second order; reaction \(\mathrm{B}\) is first order; and reaction C is zero order.

In this chapter, we have seen a number of reactions in which a single reactant forms products. For example, consider the following first-order reaction: \(\mathrm{CH}_{3} \mathrm{NC}(g) \longrightarrow \mathrm{CH}_{3} \mathrm{CN}(g)\) However, we also learned that gas-phase reactions occur through collisions. a. One possible explanation for how this reaction occurs is that two molecules of \(\mathrm{CH}_{3} \mathrm{NC}\) collide with each other and form two molecules of the product in a single elementary step. If that were the case, what reaction order would you expect? b. Another possibility is that the reaction occurs through more than one step. For example, a possible mechanism involves one step in which the two \(\mathrm{CH}_{3} \mathrm{NC}\) molecules collide, resulting in the "activation" of one of them. In a second step, the activated molecule goes on to form the product. Write down this mechanism and determine which step must be rate determining in order for the kinetics of the reaction to be first order. Show explicitly how the mechanism predicts first-order kinetics.

See all solutions

Recommended explanations on Chemistry Textbooks

View all explanations

What do you think about this solution?

We value your feedback to improve our textbook solutions.

Study anywhere. Anytime. Across all devices.

Sign-up for free