How many sulfur atoms are there in 5.52 mol of sulfur?

Short Answer

Expert verified
There are approximately 3.32 x 10^24 sulfur atoms in 5.52 mol of sulfur.

Step by step solution

01

Recall Avogadro's Number

Remember that Avogadro's number is a constant, which is approximately equal to 6.022 x 10^23. This number represents the amount of atoms, ions, or molecules in one mole of a substance.
02

Calculate the Total Number of Sulfur Atoms

To find the total number of sulfur atoms in 5.52 mol of sulfur, multiply the number of moles of sulfur by Avogadro's number: Total number of sulfur atoms = 5.52 mol x 6.022 x 10^23 atoms/mol.

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Mole Calculation
Understanding mole calculation is fundamental in chemistry as it enables students to convert between the mass of a substance and the number of atoms, molecules, or ions it contains. A mole is a unit that measures an amount of a chemical substance that contains as many representative particles, like atoms, as there are atoms in 12 grams of carbon-12. This amount is Avogadro's number, which is approximately \(6.022 \times 10^{23}\) particles per mole.

In our exercise, we are asked to determine the number of sulfur atoms in 5.52 moles of sulfur. Here's how we apply mole calculation:
  • Identify the given quantity: 5.52 moles of sulfur.
  • Use Avogadro's number to find the equivalent number of particles in the moles provided: \(5.52 \text{ mol} \times 6.022 \times 10^{23} \, \text{atoms/mol}\).
  • Calculate the product to get the total number of sulfur atoms.
Remember, mole calculation is a bridge between the microscopic world of atoms and the macroscopic world we can measure and observe.
Stoichiometry
Stoichiometry is a segment of chemistry that involves the quantitative relationships between the reactants and products in a chemical reaction. It is based on the law of conservation of mass and the law of definite proportions. Stoichiometry calculations use the balanced chemical equation to find out how much reactants are needed or how much products are created.

In practical terms, stoichiometry is used to calculate how many moles of a reactant are needed to react completely with a given number of moles of another reactant or to produce a certain amount of product. To perform these calculations, we use the coefficients from the balanced equation as mole ratios, which serve as conversion factors to relate quantities of one substance to another.

Stoichiometry extends beyond mole-to-mole conversions and includes finding the mass or volume of substances involved in a reaction, as well as calculations involving limiting reagents and percent yield. It's crucial for predicting the outcomes of reactions and for scaling reactions up from laboratory to industrial scales.
Chemical Quantity
The concept of chemical quantity is integral to understanding reactions and compounds in chemistry. It refers to the amount of a substance in terms of moles, volume, mass, or number of particles. In the context of our exercise, the chemical quantity we focus on is the number of particles, specifically the number of sulfur atoms in a given number of moles.

Chemical quantities are closely tied to Avogadro's number when dealing with particles at the atomic or molecular scale. Having a fixed number for the mole allows chemists to calculate the number of particles in a chemical sample quantitatively. This is crucial for tasks such as determining the formula of a compound, balancing chemical equations, and preparing solutions of a known concentration.

Understanding how to relate mass, moles, and the number of particles through conversion factors is essential for mastering chemistry. The mole is the bridge that allows us to translate between the macroscopic amounts we can measure and the microscopic scale of individual atoms and molecules.

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Most popular questions from this chapter

An element has two naturally occurring isotopes. Isotope 1 has a mass of 120.9038 amu and a relative abundance of \(57.4 \%\), and isotope 2 has a mass of 122.9042 amu. Find the atomic mass of this element and identify it.

The ratio of the mass of a nitrogen atom to the mass of an atom of \({ }^{12} \mathrm{C}\) is \(7: 6,\) and the ratio of the mass of nitrogen to oxygen in \(\mathrm{N}_{2} \mathrm{O}\) is \(7: 4 .\) Find the mass of \(1 \mathrm{~mol}\) of oxygen atoms.

Two samples of sodium chloride are decomposed into their constituent elements. One sample produces 6.98 g of sodium and \(10.7 \mathrm{~g}\) of chlorine, and the other sample produces \(11.2 \mathrm{~g}\) of sodium and \(17.3 \mathrm{~g}\) of chlorine. Are these results consistent with the law of definite proportions? Explain your answer.

A chemist in an imaginary universe, where electrons have a different charge than they do in our universe, performs the Millikan oil drop experiment to measure the electron's charge. The charges of several drops are recorded here. What is the charge of the electron in this imaginary universe? $$ \begin{array}{cc} \text { Drop number } & \text { Charge } \\ \hline \text { A } & -6.9 \times 10^{-19} \mathrm{C} \\ \hline \text { B } & -9.2 \times 10^{-19} \mathrm{C} \\ \hline \text { C } & -11.5 \times 10^{-19} \mathrm{C} \\ \hline \text { D } & -4.6 \times 10^{-19} \mathrm{C} \\ \hline \end{array} $$

On a dry day, your body can accumulate static charge from walking across a carpet or from brushing your hair. If your body develops a charge of \(-15 \mu\) C (microcoulombs), how many excess electrons has it acquired? What is their collective mass?

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