Consider the reaction:
$$
4 \mathrm{~K}(s)+\mathrm{O}_{2}(g) \longrightarrow 2 \mathrm{~K}_{2}
\mathrm{O}(s)
$$
The molar mass of \(\mathrm{K}\) is \(39.10 \mathrm{~g} / \mathrm{mol}\), and that
of \(\mathrm{O}_{2}\) is \(32.00 \mathrm{~g} / \mathrm{mol}\). Without doing any
calculations, pick the conditions under which potassium is the limiting
reactant and explain your reasoning.
a. \(170 \mathrm{~g} \mathrm{~K}, 31 \mathrm{~g} \mathrm{O}_{2}\)
b. \(16 \mathrm{~g} \mathrm{~K}, 2.5 \mathrm{~g} \mathrm{O}_{2}\)
c. \(165 \mathrm{~kg} \mathrm{~K}, 28 \mathrm{~kg} \mathrm{O}_{2}\)
d. \(1.5 \mathrm{~g} \mathrm{~K}, 0.38 \mathrm{~g} \mathrm{O}_{2}\)