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Chapter 1: Problem 39

In an experiment it was found that the total charge on an oil drop was \(5.93 \times 10^{-18} \mathrm{C}\). How many negative charges does the drop contain?

Short Answer

Expert verified
The oil drop contains approximately 37 negative charges (electrons).

Step by step solution

01

Identify given values

We are given the total charge on the oil drop (\(Q\)) and the charge of an electron (\(e\)). - Total charge on the oil drop (\(Q\)) = \(5.93 \times 10^{-18} \mathrm{C}\) - Charge of an electron (\(e\)) = \(1.60 \times 10^{-19} \mathrm{C}\)
02

Use the formula to find the number of negative charges

We'll divide the total charge (\(Q\)) by the charge of a single electron (\(e\)) to find the number of negative charges (electrons) on the oil drop: Number of negative charges (\(n\)) = \(\frac{Q}{e}\)
03

Calculate the number of negative charges

Plug the given values into the formula: \(n = \dfrac{5.93 \times 10^{-18} \mathrm{C}}{1.60 \times 10^{-19} \mathrm{C}}\) Now, we'll perform the calculation: \(n = 37.06\)
04

Round the result and state the final answer

Since the number of negative charges must be a whole number, we'll round the result to the nearest whole number: \(n \approx 37\) Hence, the oil drop contains approximately 37 negative charges (electrons).

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