Log out Go to App
Go to App

Learning Materials

Features

Discover

Chapter 10: Problem 116

A \(4.7 \times 10^{-2}\) mg sample of a protein is dissolved in water to make \(0.25 \mathrm{mL}\) of solution. The osmotic pressure of the solution is 0.56 torr at \(25^{\circ} \mathrm{C}\). What is the molar mass of the protein?

Short Answer

Expert verified
The molar mass of the protein is approximately 75,440 g/mol.

Step by step solution

01

Convert the given values into appropriate units

First, we need to convert the given values into appropriate units: Mass of protein = \(4.7 \times 10^{-2}\) mg = \(4.7 \times 10^{-5}\) g (1 g/1000 mg) Volume of solution = 0.25 mL = 0.00025 L (1 L/1000 mL) Osmotic pressure = 0.56 torr = 0.000736 atm (1 atm/760 torr) Temperature = 25°C = 298.15 K (273.15 + 25)
02

Calculate the number of moles of the protein using osmotic pressure formula

Using the osmotic pressure formula, we can calculate the number of moles of the protein: Osmotic pressure = (Molarity) × (R) × (Temperature) Rearrange the formula to find molarity: Molarity = Osmotic pressure / (R × Temperature) Plug in the given values: Molarity = 0.000736 atm / (0.0821 L·atm/mol·K × 298.15 K) Molarity = \(2.49 \times 10^{-6}\) mol/L
03

Find the number of moles of protein in the given volume of solution

Now, we can find the number of moles of the protein in the 0.00025 L solution using the calculated molarity: Number of moles = Molarity × Volume of solution Number of moles = \(2.49 \times 10^{-6}\) mol/L × 0.00025 L Number of moles = \(6.23 \times 10^{-10}\) mol
04

Calculate the molar mass of the protein

Finally, use the mass of the protein sample and the number of moles to find the molar mass of the protein: Molar mass = Mass of protein / Number of moles Molar mass = \(4.7 \times 10^{-5}\) g / \(6.23 \times 10^{-10}\) mol Molar mass = 75,440 g/mol The molar mass of the protein is approximately 75,440 g/mol.

Unlock Step-by-Step Solutions & Ace Your Exams!

  • Full Textbook Solutions

    Get detailed explanations and key concepts

  • Unlimited Al creation

    Al flashcards, explanations, exams and more...

  • Ads-free access

    To over 500 millions flashcards

  • Money-back guarantee

    We refund you if you fail your exam.

Start your free trial

Over 30 million students worldwide already upgrade their learning with Vaia!

One App. One Place for Learning.

All the tools & learning materials you need for study success - in one app.

Get started for free

Most popular questions from this chapter

What stabilizes a colloidal suspension? Explain why adding heat or adding an electrolyte can cause the suspended particles to settle out.

Which of the following will have the lowest total vapor pressure at \(25^{\circ} \mathrm{C} ?\) a. pure water (vapor pressure \(=23.8\) torr at \(25^{\circ} \mathrm{C}\) ) b. a solution of glucose in water with \(\chi_{\mathrm{C}_{\mathrm{s}} \mathrm{H}_{\mathrm{l} 2} \mathrm{O}_{\mathrm{s}}}=0.01\) c. a solution of sodium chloride in water with \(\chi_{\mathrm{NaCl}}=0.01\) d. a solution of methanol in water with \(\chi_{\mathrm{CH_{3}}, \mathrm{OH}}=0.2\) (Consider the vapor pressure of both methanol \([143\) torr at \(\left.25^{\circ} \mathrm{C}\right]\) and water.

A 0.15 -g sample of a purified protein is dissolved in water to give \(2.0 \mathrm{mL}\) of solution. The osmotic pressure is found to be 18.6 torr at \(25^{\circ} \mathrm{C} .\) Calculate the protein's molar mass.

The freezing point of \(t\) -butanol is \(25.50^{\circ} \mathrm{C}\) and \(K_{\mathrm{f}}\) is \(9.1^{\circ} \mathrm{C} \cdot \mathrm{kg} /\) mol. Usually \(t\) -butanol absorbs water on exposure to air. If the freezing point of a 10.0 -g sample of \(t\) -butanol is \(24.59^{\circ} \mathrm{C},\) how many grams of water are present in the sample?

Using the phase diagram for water and Raoult's law, explain why salt is spread on the roads in winter (even when it is below freezing).
See all solutions

Recommended explanations on Chemistry Textbooks

Physical Chemistry

Read Explanation

Nuclear Chemistry

Read Explanation

Chemical Reactions

Read Explanation

Chemistry Branches

Read Explanation

The Earths Atmosphere

Read Explanation

Making Measurements

Read Explanation
View all explanations

What do you think about this solution?

We value your feedback to improve our textbook solutions.

Study anywhere. Anytime. Across all devices.

Sign-up for free