Chapter 10: Problem 49
The solubility of nitrogen in water is \(8.21 \times 10^{-4} \mathrm{mol} / \mathrm{L}\) at \(0^{\circ} \mathrm{C}\) when the \(\mathrm{N}_{2}\) pressure above water is 0.790 atm. Calculate the Henry's law constant for \(\mathrm{N}_{2}\) in units of mol/L \cdot atm for Henry's law in the form \(C=k P,\) where \(C\) is the gas concentration in mol/L. Calculate the solubility of \(\mathrm{N}_{2}\) in water when the partial pressure of nitrogen above water is 1.10 atm at \(0^{\circ} \mathrm{C}\).
Short Answer
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Key Concepts
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