Consider the following solutions: \(0.010 m \mathrm{Na}_{3} \mathrm{PO}_{4}\) in water \(0.020 \mathrm{m} \mathrm{CaBr}_{2}\) in water \(0.020 \mathrm{m} \mathrm{KCl}\) in water \(0.020 \mathrm{m}\) HF in water (HF is a weak acid.) a. Assuming complete dissociation of the soluble salts, which solution(s) would have the same boiling point as \(0.040 \mathrm{m}\) \(\mathrm{C}_{6} \mathrm{H}_{12} \mathrm{O}_{6}\) in water? \(\mathrm{C}_{6} \mathrm{H}_{12} \mathrm{O}_{6}\) is a nonelectrolyte. b. Which solution would have the highest vapor pressure at \(28^{\circ} \mathrm{C} ?\) c. Which solution would have the largest freezing-point depression?

Short Answer

Expert verified
a) The Na3PO4 and KCl solutions will have the same boiling point as the 0.040 m C6H12O6 solution. b) The HF solution will have the highest vapor pressure at 28°C. c) The CaBr2 solution will have the largest freezing-point depression.

Step by step solution

01

Calculate the molality for each solution

Since the given molality values are provided directly, we don't need to make any calculations for molality. We already have the molality for each of the solutions: - 0.010 m Na3PO4 - 0.020 m CaBr2 - 0.020 m KCl - 0.020 m HF - 0.040 m C6H12O6 (reference)
02

Determine the Van't Hoff factor (i) for each solution

For non-electrolytes like C6H12O6, i=1. For electrolytes, i is equal to the number of ions produced on dissociation: - Na3PO4: 3 Na+ + PO4^3- → i = 4 - CaBr2: Ca^2+ + 2 Br- → i = 3 - KCl: K+ + Cl- → i = 2 - HF: weak acid, doesn't completely dissociate → i ≈ 1
03

Calculate i×molality for each solution

Multiply molality and the number of ions produced(i) for each solution: - Na3PO4: 0.010 m × 4 = 0.040 - CaBr2: 0.020 m × 3 = 0.060 - KCl: 0.020 m × 2 = 0.040 - HF: 0.020 m × 1 ≈ 0.020 - C6H12O6: 0.040 m × 1 = 0.040 (reference) a) The solutions which have the same i×molality as the C6H12O6 solution will have the same boiling point. Both Na3PO4 and KCl solutions show the same i×molality value (0.040) as C6H12O6. b) The highest vapor pressure will be produced by the solution with the lowest molality. In this case, the HF solution has the lowest i×molality, so it will have the highest vapor pressure at 28°C. c) The largest freezing-point depression will occur in the solution with the highest i×molality. So, CaBr2 with i×molality value of 0.060 will have the largest freezing-point depression. Answers: a) The Na3PO4 and KCl solutions will have the same boiling point as the 0.040 m C6H12O6 solution. b) The HF solution will have the highest vapor pressure at 28°C. c) The CaBr2 solution will have the largest freezing-point depression.

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