Ammonia is produced by the Haber process, in which nitrogen and hydrogen are reacted directly using an iron mesh impregnated with oxides as a catalyst. For the reaction $$\mathrm{N}_{2}(g)+3 \mathrm{H}_{2}(g) \rightleftharpoons 2 \mathrm{NH}_{3}(g)$$.equilibrium constants \(\mathbf{r}_{\mathbf{p}}\).\(300^{\circ} \mathrm{C}, \quad 4.34 \times 10^{-3}\) \(500^{\circ} \mathrm{C}, \quad 1.45 \times 10^{-5}\) \(600^{\circ} \mathrm{C}, \quad 2.25 \times 10^{-6}\) Is the reaction exothermic or endothermic?

Short Answer

Expert verified
The reaction is exothermic because the equilibrium constant decreases with an increase in temperature, indicating a negative enthalpy change (ΔH).

Step by step solution

01

Observe the equilibrium constants' behavior at different temperatures

Observe the given equilibrium constants (K) and their corresponding temperatures (T): - \(300^{\circ} \mathrm{C}\) and K = \(4.34 \times 10^{-3}\) - \(500^{\circ} \mathrm{C}\) and K = \(1.45 \times 10^{-5}\) - \(600^{\circ} \mathrm{C}\) and K = \(2.25 \times 10^{-6}\) As the temperature increases from \(300^{\circ} \mathrm{C}\) to \(500^{\circ} \mathrm{C}\) and further to \(600^{\circ} \mathrm{C}\), the equilibrium constant decreases.
02

Determine the nature of the reaction

Since the equilibrium constant decreases with an increase in temperature, the reaction is exothermic. The negative enthalpy change (ΔH) causes the decrease in equilibrium constant as the temperature increases. So, the given reaction is exothermic.

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Chemical Equilibrium
The behavior of chemical reactions can be quite complex, especially when they reach a state called chemical equilibrium. Imagine a busy downtown where traffic is coming from different directions, and at some point, the number of cars entering is equal to the number leaving – that's a simple way of looking at equilibrium in a reaction.

When a reaction reaches chemical equilibrium, the rates of the forward and reverse reactions are equal. This means that the concentrations of the reactants and products remain constant over time, but not necessarily equal, because the system is balanced. It's important to note that equilibrium represents a dynamic balance; even though concentrations remain constant, the reactants are still converting into products and vice versa, but at identical rates.

In the case of the Haber process for producing ammonia, nitrogen and hydrogen gases react to form ammonia, and this reaction can also reverse – ammonia can decompose back into nitrogen and hydrogen. Equilibrium is reached when the rate of formation of ammonia equals the rate of its decomposition.
Equilibrium Constant
The equilibrium constant, represented by the symbol K, is a number that provides a lot of information about a chemical reaction at equilibrium. It's like a scorecard that tells you which team is 'winning' in a sports game where the teams are the reactants and products in a chemical reaction.

Mathematically, it's determined by the ratio of the product of the concentrations of the products to the product of the concentrations of the reactants, each raised to the power of their respective coefficients from the balanced chemical equation. For the Haber process the equation looks like this: \( K = \frac{[NH_3]^2}{[N_2][H_2]^3} \).

The magnitude of the equilibrium constant gives us insight into the position of the equilibrium: a larger value, much greater than 1, means there's more product than reactant, while a smaller value, much less than 1, suggests there's more reactant. The given equilibrium constants for the Haber process at different temperatures show this 'score' changes with temperature, implying the position of equilibrium shifts with temperature changes.
Exothermic Reaction
An exothermic reaction is one that releases heat; it's like a natural hand warmer providing toasty warmth on a cold day. In other words, it's a chemical reaction that results in a net release of energy to the surroundings - think of it as the chemical formula for a miniature sun.

The heat released during these reactions can often be felt or measured with a thermometer. In the context of the Haber process, we can infer that it is exothermic because as the temperature is increased, the equilibrium constant decreases. It's like the reaction doesn't 'want' to form as much product at higher temperatures because it's already getting heat from the surroundings, which is enough to satisfy its energy release 'needs'.

Physically, this decrease in the equilibrium constant with increasing temperature supports the idea that heat is a product of the reaction – and according to Le Chatelier's principle, adding more of a product, in this case heat, will shift the equilibrium to favor the reactants, hence the decrease in equilibrium constant values.

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Most popular questions from this chapter

Le Châtelier's principle is stated (Section \(12-7\) ) as follows: "If a change is imposed on a system at equilibrium, the position of the equilibrium will shift in a direction that tends to reduce that change." The system \(\mathrm{N}_{2}(g)+3 \mathrm{H}_{2}(g) \rightleftharpoons 2 \mathrm{NH}_{3}(g)\) is used as an example in which the addition of nitrogen gas at equilibrium results in a decrease in \(\mathrm{H}_{2}\) concentration and an increase in \(\mathrm{NH}_{3}\) concentration. In the experiment the volume is assumed to be constant. On the other hand, if \(\mathrm{N}_{2}\) is added to the reaction system in a container with a piston so that the pressure can be held constant, the amount of \(\mathrm{NH}_{3}\) actually could decrease, and the concentration of \(\mathrm{H}_{2}\) would increase as equilibrium is reestablished. Explain how this can happen. Also, if you consider this same system at equilibrium, the addition of an inert gas, holding the pressure constant, does affect the equilibrium position. Explain why the addition of an inert gas to this system in a rigid container does not affect the equilibrium position.

The following equilibrium pressures were observed at a certain temperature for the reaction $$\begin{array}{c}\mathrm{N}_{2}(g)+3 \mathrm{H}_{2}(g) \rightleftharpoons 2 \mathrm{NH}_{3}(g) \\\P_{\mathrm{NH}}=3.1 \times 10^{-2} \mathrm{atm} \\\P_{\mathrm{N}_{2}}=8.5 \times 10^{-1} \mathrm{atm} \\\P_{\mathrm{H}_{2}}=3.1 \times 10^{-3} \mathrm{atm}\end{array}$$.Calculate the value for the equilibrium constant \(K_{\mathrm{p}}\) at this temperature. If \(P_{\mathrm{N}_{2}}=0.525\) atm, \(P_{\mathrm{NH},}=0.0167\) atm, and \(P_{\mathrm{H}_{2}}=0.00761\) atm, does this represent a system at equilibrium?

The creation of shells by mollusk species is a fascinating process. By utilizing the \(\mathrm{Ca}^{2+}\) in their food and aqueous environment, as well as some complex equilibrium processes, a hard calcium carbonate shell can be produced. One important equilibrium reaction in this complex process is \(\mathrm{HCO}_{3}^{-}(a q) \rightleftharpoons \mathrm{H}^{+}(a q)+\mathrm{CO}_{3}^{2-}(a q) \quad K=5.6 \times 10^{-11}\) If 0.16 mole of \(\mathrm{HCO}_{3}^{-}\) is placed into \(1.00 \mathrm{~L}\) of solution, what will be the equilibrium concentration of \(\mathrm{CO}_{3}{ }^{2-}\) ?

For the reaction \(\mathrm{H}_{2}(g)+\mathrm{I}_{2}(g) \rightleftharpoons 2 \mathrm{HI}(g),\) consider two possibilities: (a) you mix 0.5 mole of each reactant, allow the system to come to equilibrium, and then add another mole of \(\mathrm{H}_{2}\) and allow the system to reach equilibrium again, or (b) you mix 1.5 moles of \(\mathrm{H}_{2}\) and 0.5 mole of \(\mathrm{I}_{2}\) and allow the system to reach equilibrium. Will the final equilibrium mixture be different for the two procedures? Explain.

For the reaction $$\mathrm{PCl}_{5}(g) \rightleftharpoons \mathrm{PCl}_{3}(g)+\mathrm{Cl}_{2}(g)$$ at \(600 . \mathrm{K},\) the equilibrium constant, \(K_{\mathrm{p}},\) is \(11.5 .\) Suppose that \(2.450 \mathrm{g} \mathrm{PCl}_{5}\) is placed in an evacuated \(500 .-\mathrm{mL}\) bulb, which is then heated to \(600 .\) K. a. What would be the pressure of \(\mathrm{PCl}_{5}\) if it did not dissociate? b. What is the partial pressure of \(\mathrm{PCl}_{5}\) at equilibrium? c. What is the total pressure in the bulb at equilibrium? d. What is the percent dissociation of \(\mathrm{PCl}_{5}\) at equilibrium?

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