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Chapter 13: Problem 136

Will the following oxides give acidic, basic, or neutral solutions when dissolved in water? Write reactions to justify your answers. a. \(\mathrm{Li}_{2} \mathrm{O}\) b. \(\mathrm{CO}_{2}\) c. SrO

Short Answer

Expert verified
When dissolved in water: a. Lithium oxide (\(\mathrm{Li}_{2} \mathrm{O}\)) will give a basic solution. Reaction: \[\mathrm{Li}_{2} \mathrm{O (s)} + \mathrm{H}_{2} \mathrm{O (l)} \rightarrow 2 \mathrm{LiOH (aq)}\] b. Carbon dioxide (\(\mathrm{CO}_{2}\)) will give an acidic solution. Reaction: \[\mathrm{CO}_{2} \mathrm{(g)} + \mathrm{H}_{2} \mathrm{O (l)} \rightarrow \mathrm{H}_{2} \mathrm{CO}_{3 \mathrm{(aq)}}\] c. Strontium oxide (SrO) will give a basic solution. Reaction: \[\mathrm{SrO (s)} + \mathrm{H}_{2} \mathrm{O (l)} \rightarrow \mathrm{Sr}(\mathrm{OH})_{2} \mathrm{(aq)}\]

Step by step solution

01

Part a: Lithium oxide (\(\mathrm{Li}_{2} \mathrm{O}\))

Lithium oxide (Li2O) is an ionic compound formed by the reaction between lithium and oxygen. As lithium is an alkali metal, its oxide is a basic oxide. Therefore, when lithium oxide dissolves in water, it will give a basic solution. The reaction between Li2O and water is as follows: \[\mathrm{Li}_{2} \mathrm{O (s)} + \mathrm{H}_{2} \mathrm{O (l)} \rightarrow 2 \mathrm{LiOH (aq)}\] The lithium oxide reacts with water to form lithium hydroxide (LiOH), a strong base that increases the pH of the solution.
02

Part b: Carbon dioxide (\(\mathrm{CO}_{2}\))

Carbon dioxide (CO2) is a non-metal oxide, specifically an acidic oxide. When it dissolves in water, it forms a weak acid known as carbonic acid (H2CO3). The reaction between CO2 and water is as follows: \[\mathrm{CO}_{2} \mathrm{(g)} + \mathrm{H}_{2} \mathrm{O (l)} \rightarrow \mathrm{H}_{2} \mathrm{CO}_{3 \mathrm{(aq)}}\] As the resulting solution contains an acidic species (carbonic acid), the solution will be acidic.
03

Part c: Strontium oxide (SrO)

Strontium oxide (SrO) is a basic oxide, as strontium is an alkaline earth metal. Thus when it dissolves in water, it forms a basic solution. The reaction between SrO and water is as follows: \[\mathrm{SrO (s)} + \mathrm{H}_{2} \mathrm{O (l)} \rightarrow \mathrm{Sr}(\mathrm{OH})_{2} \mathrm{(aq)}\] The strontium oxide reacts with water to form strontium hydroxide (Sr(OH)2), a strong base, which therefore results in a basic solution.

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Most popular questions from this chapter

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