A friend asks the following: "Consider a buffered solution made up of the weak acid HA and its salt NaA. If a strong base like NaOH is added, the HA reacts with the OH - to form A Thus the amount of acid (HA) is decreased, and the amount of base \(\left(\mathrm{A}^{-}\right)\) is increased. Analogously, adding HCl to the buffered solution forms more of the acid (HA) by reacting with the base \(\left(\mathrm{A}^{-}\right)\). Thus how can we claim that a buffered solution resists changes in the pH of the solution?" How would you explain buffering to this friend?

Short Answer

Expert verified
A buffered solution resists changes in pH due to the equilibrium between the weak acid (HA) and its conjugate base (A-). When a strong acid or base is added, the equilibrium shifts to counteract the effects of the added acid or base, maintaining the pH. This can be explained using the Henderson-Hasselbalch equation: \(pH = pK_a + \log \frac{[A^-]}{[HA]}\). The solution's pH remains relatively constant when the ratio of the conjugate base to the weak acid does not significantly change, even when a small amount of strong acid or base is added.

Step by step solution

01

Understanding a Buffered Solution

A buffered solution is a mixture of a weak acid (HA) and its conjugate base, which is usually a salt (NaA). In this context, the weak acid (HA) donates a proton (H+) to the solution, while the conjugate base (A-) accepts a proton. The ratio of the acid to its conjugate base in the solution determines the pH of the buffered solution. The combination of weak acid and its conjugate base has the ability to maintain a relatively constant pH despite the addition of a small amount of strong acid or base.
02

Reactions when a strong base is added

When a strong base (like NaOH) is added to the buffered solution, it reacts with the weak acid (HA) in the solution, neutralizing it. The reaction is given by: \[HA + OH^- \rightarrow A^- + H_2O\] As a result, the concentration of the weak acid (HA) decreases, and the concentration of its conjugate base (A-) increases.
03

Reactions when a strong acid is added

Conversely, when a strong acid (like HCl) is added to the buffered solution, it reacts with the conjugate base (A-) present in the solution. The reaction is as follows: \[A^- + H^+ \rightarrow HA\] In this case, the concentration of the conjugate base (A-) decreases, and the concentration of the weak acid (HA) increases.
04

Buffering action explained

The buffering action is due to the equilibrium that exists between the weak acid (HA) and its conjugate base (A-) in the solution. When a strong base or acid is added, the equilibrium shifts in a direction to counteract the effect of the added base or acid. In the case of a strong base being added, the equilibrium shifts to the right, removing the excess hydroxide ions (OH-) and maintaining the pH. When a strong acid is added, the equilibrium shifts to the left, removing the excess hydrogen ions (H+) and again preserving the pH.
05

Using the Henderson-Hasselbalch Equation

The pH stability of a buffered solution can be explained using the Henderson-Hasselbalch equation: \[pH = pK_a + \log \frac{[A^-]}{[HA]}\] Here, \(pK_a\) is the negative logarithm of the acid dissociation constant of the weak acid (HA). When the ratio of the conjugate base (A-) to the weak acid (HA) remains relatively constant, the pH of the buffered solution also remains relatively constant. The addition of small amounts of strong acid or base will not significantly change the ratio of the two components, hence the pH is maintained. In conclusion, a buffered solution resists changes in pH by maintaining a constant ratio of weak acid to its conjugate base, even when a strong acid or base is added to the solution. It counteracts the added acid or base by shifting the acid-base equilibrium, thus maintaining the buffered solution's pH.

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Most popular questions from this chapter

A certain indicator HIn has a \(\mathrm{p} K_{\mathrm{a}}\) of 3.00 and a color change becomes visible when \(7.00 \%\) of the indicator has been converted to \(\operatorname{In}^{-} .\) At what \(\mathrm{pH}\) is this color change visible?

A \(10.00-g\) sample of the ionic compound \(\mathrm{NaA}\), where \(\mathrm{A}^{-}\) is the anion of a weak acid, was dissolved in enough water to make 100.0 mL of solution and was then titrated with 0.100 \(M\) HCl. After 500.0 mL HCl was added, the pH was \(5.00 .\) The experimenter found that 1.00 L of \(0.100 M\) HCl was required to reach the stoichiometric point of the titration. a. What is the molar mass of NaA? b. Calculate the \(p\) H of the solution at the stoichiometric point of the titration.

When a person exercises, muscle contractions produce lactic acid. Moderate increases in lactic acid can be handled by the blood buffers without decreasing the pH of blood. However, excessive amounts of lactic acid can overload the blood buffer system, resulting in a lowering of the blood pH. A condition called acidosis is diagnosed if the blood pH falls to 7.35 or lower. Assume the primary blood buffer system is the carbonate buffer system described in Exercise \(45 .\) Calculate what happens to the \(\left[\mathrm{H}_{2} \mathrm{CO}_{3}\right] /\left[\mathrm{HCO}_{3}^{-}\right]\) ratio in blood when the \(\mathrm{pH}\) decreases from 7.40 to 7.35.

One method for determining the purity of aspirin \(\left(\mathrm{C}_{9} \mathrm{H}_{8} \mathrm{O}_{4}\right)\) is to hydrolyze it with NaOH solution and then to titrate the remaining NaOH. The reaction of aspirin with NaOH is as follows: $$\begin{aligned} &\mathrm{C}_{9} \mathrm{H}_{8} \mathrm{O}_{4}(s)+2 \mathrm{OH}^{-}(a q)\\\&\text { Aspirin } \quad \frac{\text { Boil }}{10 \min } \underset{\text { Salicylate ion }}{\mathrm{C}_{7} \mathrm{H}_{5} \mathrm{O}_{3}^{-}(a q)}+\mathrm{C}_{2} \mathrm{H}_{3} \mathrm{O}_{2}^{-}(a q)+\mathrm{H}_{2} \mathrm{O}(l) \end{aligned}$$ A sample of aspirin with a mass of 1.427 g was boiled in \(50.00 \mathrm{mL}\) of \(0.500 \mathrm{M} \mathrm{NaOH} .\) After the solution was cooled, it took \(31.92 \mathrm{mL}\) of \(0.289 \mathrm{M}\) HCl to titrate the excess NaOH. Calculate the purity of the aspirin. What indicator should be used for this titration? Why?

Calculate the \(\mathrm{pH}\) of each of the following buffered solutions. a. \(0.10 M\) acetic acid/0.25 \(M\) sodium acetate b. \(0.25 M\) acetic acid/0.10 \(M\) sodium acetate c. \(0.080 M\) acetic acid/0.20 \(M\) sodium acetate d. \(0.20 M\) acetic acid/0.080 \(M\) sodium acetate

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