Consider the reaction $$\mathrm{Fe}_{2} \mathrm{O}_{3}(s)+3 \mathrm{H}_{2}(g) \longrightarrow 2 \mathrm{Fe}(s)+3 \mathrm{H}_{2} \mathrm{O}(g)$$ a. Use \(\Delta G_{\mathrm{f}}^{\circ}\) values in Appendix 4 to calculate \(\Delta G^{\circ}\) for this reaction. b. Is this reaction spontaneous under standard conditions at \(298 \mathrm{K} ?\) c. The value of \(\Delta H^{\circ}\) for this reaction is \(100 .\) kJ. At what temperatures is this reaction spontaneous at standard conditions? Assume that \(\Delta H^{\circ}\) and \(\Delta S^{\circ}\) do not depend on temperature.

Short Answer

Expert verified
We first calculate the standard Gibbs free energy change (\(\Delta G^{\circ}\)) for the reaction using the given standard Gibbs free energy of formation values \(\Delta Gf^{\circ}\) and the formula: \(\Delta G^{\circ} = \sum n \Delta G_{f}^{\circ}(\text{products}) - \sum n \Delta G_{f}^{\circ}(\text{reactants})\) Then, we determine the spontaneity of the reaction at 298 K by comparing the calculated \(\Delta G^{\circ}\) value with zero. If \(\Delta G^{\circ} < 0\), the reaction is spontaneous under standard conditions at 298 K. Lastly, to find the temperature range in which the reaction is spontaneous under standard conditions, we use the relationship between Gibbs free energy, enthalpy, and entropy: \(\Delta G^{\circ} = \Delta H^{\circ} - T\Delta S^{\circ}\) We determine \(\Delta S^{\circ}\) using the given \(\Delta H^{\circ}\) value, and then find the temperature range in which \(\Delta G^{\circ} < 0\).

Step by step solution

01

Write the balanced equation for the reaction

Given the balanced equation: \(\mathrm{Fe}_{2} \mathrm{O}_{3}(s)+3 \mathrm{H}_{2}(g) \longrightarrow 2 \mathrm{Fe}(s)+3 \mathrm{H}_{2} \mathrm{O}(g)\) Now, find the standard Gibbs free energy change for this reaction using the standard Gibbs free energy of formation values.
02

Calculate the ΔG° using the ΔGf° values

Use the formula: \(\Delta G^{\circ} = \sum n \Delta G_{f}^{\circ}(\text{products}) - \sum n \Delta G_{f}^{\circ}(\text{reactants})\) Where n is the stoichiometric coefficient, and \(\Delta G_{f}^{\circ}\) is the standard Gibbs free energy of formation. The values for ΔGf° can be found in Appendix 4. For this reaction: \(\Delta G^{\circ} = (2\Delta G_{f}^{\circ}(\mathrm{Fe}) + 3\Delta G_{f}^{\circ}(\mathrm{H}_{2}\mathrm{O}) - (\Delta G_{f}^{\circ}(\mathrm{Fe}_{2} \mathrm{O}_{3}) + 3\Delta G_{f}^{\circ}(\mathrm{H}_{2}))\)
03

Determine if the reaction is spontaneous at 298 K

The reaction is spontaneous under standard conditions at 298 K if \(\Delta G^{\circ} < 0\). Compare the calculated \(\Delta G^{\circ}\) value with zero to check the spontaneity of the reaction.
04

Find the temperature range for spontaneous reaction

We are given that the standard enthalpy change for the reaction is 100 kJ, and we need to find the temperature range for which the reaction is spontaneous. We can use the relationship between Gibbs free energy, enthalpy, and entropy: \(\Delta G^{\circ} = \Delta H^{\circ} - T\Delta S^{\circ}\) where T is the temperature in Kelvin, and ΔS° is the standard entropy change. First, determine \(\Delta S^{\circ}\) using the relationship: \(\Delta S^{\circ} = \frac{\Delta H^{\circ} - \Delta G^{\circ}}{T}\) Then, find the temperature range in which \(\Delta G^{\circ} < 0\) under standard conditions (\(\Delta H^{\circ}\) and \(\Delta S^{\circ}\) do not depend on temperature). In other words, find the temperature range in which: \(\Delta H^{\circ} - T\Delta S^{\circ} < 0\)

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Most popular questions from this chapter

At \(1500 \mathrm{K},\) the process $$\begin{aligned} &\mathbf{I}_{2}(g) \longrightarrow 2 \mathbf{I}(g)\\\ &10 \mathrm{atm} \quad 10 \mathrm{atm} \end{aligned}$$ is not spontaneous. However, the process $$\begin{aligned} &\mathbf{I}_{2}(g) \longrightarrow 2 \mathbf{I}(g)\\\ &0.10 \mathrm{atm} \quad 0.10 \mathrm{atm} \end{aligned}$$ is spontaneous at \(1500 \mathrm{K}\). Explain.

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Consider the system $$\mathrm{A}(g) \longrightarrow \mathrm{B}(g)$$ at $$25^{\circ} \mathrm{C}$$ a. Assuming that \(G_{A}^{\circ}=8996 \mathrm{J} / \mathrm{mol}\) and \(G_{\mathrm{B}}^{\circ}=11,718 \mathrm{J} / \mathrm{mol}\) calculate the value of the equilibrium constant for this reaction. b. Calculate the equilibrium pressures that result if 1.00 mole of \(\mathrm{A}(g)\) at 1.00 atm and 1.00 mole of \(\mathrm{B}(g)\) at 1.00 atm are mixed at \(25^{\circ} \mathrm{C}.\) c. Show by calculations that \(\Delta G=0\) at equilibrium.

Consider the reaction: $$\mathrm{PCl}_{3}(g)+\mathrm{Cl}_{2}(g) \rightleftharpoons \mathrm{PCl}_{5}(g)$$ At \(25^{\circ} \mathrm{C}, \Delta H^{\circ}=-92.50 \mathrm{kJ}\) Which of the following statements is(are) true? a. This is an endothermic reaction. b. \(\Delta S^{\circ}\) for this reaction is negative. c. If the temperature is increased, the ratio \(\frac{\mathrm{PCl}_{5}}{\mathrm{PCl}_{3}}\) will increase. d. \(\Delta G^{\circ}\) for this reaction has to be negative at all temperatures. e. When \(\Delta G^{\circ}\) for this reaction is negative, then \(K_{\mathrm{p}}\) is greater than 1.00.

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