Combine the equations $$ \Delta G^{\circ}=-n F \mathscr{E}^{\circ} \quad \text { and } \quad \Delta G^{\circ}=\Delta H^{\circ}-T \Delta S^{\circ} $$ to derive an expression for \(\mathscr{E}^{\circ}\) as a function of temperature. Describe how one can graphically determine \(\Delta H^{\circ}\) and \(\Delta S^{\circ}\) from measurements of \(\mathscr{E}^{\circ}\) at different temperatures, assuming that \(\Delta H^{\circ}\) and \(\Delta S^{\circ}\) do not depend on temperature. What property would you look for in designing a reference half-cell that would produce a potential relatively stable with respect to temperature?

Short Answer

Expert verified
We derived the expression for \(\mathscr{E}^{\circ}\) as a function of temperature: \(\mathscr{E}^{\circ} = \frac{-\Delta H^{\circ}}{nF} + \frac{T \Delta S^{\circ}}{nF}\). To graphically determine \(\Delta H^{\circ}\) and \(\Delta S^{\circ}\), plot \(\mathscr{E}^{\circ}\) as a function of temperature, giving a linear graph with the slope as \(\frac{\Delta S^{\circ}}{nF}\) and the y-intercept as \(\frac{-\Delta H^{\circ}}{nF}\). Calculate the slope and y-intercept to solve for \(\Delta H^{\circ}\) and \(\Delta S^{\circ}\). To design a reference half-cell with a stable potential relative to temperature, look for a reference half-cell with a small or zero value for \(\Delta S^{\circ}\).

Step by step solution

01

To start, we need to combine the given equations. We will use the fact that both equations have the same term, \(\Delta G^{\circ}\), to do this. From the given equations, we get: \(-nF \mathscr{E}^{\circ} = \Delta H^{\circ} - T \Delta S^{\circ}\) #Step 2: Derive an expression for \(\mathscr{E}^{\circ}\) as a function of temperature#

To derive an expression for \(\mathscr{E}^{\circ}\) in terms of temperature, solve for \(\mathscr{E}^{\circ}\): \(\mathscr{E}^{\circ} = \frac{\Delta H^{\circ}}{-nF} + \frac{T \Delta S^{\circ}}{-nF}\) Now we have an expression for \(\mathscr{E}^{\circ}\) as a function of temperature: \(\mathscr{E}^{\circ} = \frac{-\Delta H^{\circ}}{nF} + \frac{T \Delta S^{\circ}}{nF}\) #Step 3: Graphically determine \(\Delta H^{\circ}\) and \(\Delta S^{\circ}\)#
02

To graphically determine \(\Delta H^{\circ}\) and \(\Delta S^{\circ}\) from measurements of \(\mathscr{E}^{\circ}\) at different temperatures, follow these steps: 1. Plot \(\mathscr{E}^{\circ}\) as a function of temperature (T) using the derived expression. 2. This will give a linear graph, where the slope is \(\frac{\Delta S^{\circ}}{nF}\) and the y-intercept is \(\frac{-\Delta H^{\circ}}{nF}\). 3. Calculate the slope and y-intercept of the linear graph. 4. Solve for \(\Delta H^{\circ}\) and \(\Delta S^{\circ}\) using the values of the slope and y-intercept. #Step 4: Identify the property for a reference half-cell with stable potential#

Since we want the reference half-cell to have a potential relatively stable with respect to temperature, we should look for a reference half-cell with a small or zero value for the temperature-dependent term in the expression we derived: \(\frac{T \Delta S^{\circ}}{nF}\) Ideally, we would want a reference half-cell with a nearly zero value for \(\Delta S^{\circ}\), as this would minimize the effect of temperature on the potential. In summary, we have derived an expression for \(\mathscr{E}^{\circ}\) as a function of temperature, and discussed how to graphically determine \(\Delta H^{\circ}\) and \(\Delta S^{\circ}\) from measurements of \(\mathscr{E}^{\circ}\) at different temperatures. To design a reference half-cell with a potential relatively stable with respect to temperature, we should look for a reference half-cell with a small or zero value for \(\Delta S^{\circ}\).

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Gibbs Free Energy Equation
The Gibbs free energy equation is a fundamental part of understanding how electrochemical reactions proceed. It is expressed as \(\Delta G = \Delta H - T\Delta S\), where \(\Delta G\) is the change in Gibbs free energy, \(\Delta H\) is the change in enthalpy, \(T\) is the absolute temperature, and \(\Delta S\) is the change in entropy.

In the context of electrochemical cells, this equation allows us to predict whether a reaction will occur spontaneously. A negative value of \(\Delta G\) indicates the reaction is energetically favorable, while a positive value means it is not spontaneous under the given conditions. This understanding is instrumental when analyzing the feasibility and directionality of electrochemical reactions.
Enthalpy
Enthalpy, denoted by \(\Delta H\), represents the heat transferred during a chemical reaction at constant pressure. It's an essential thermodynamic quantity that reflects the energy changes associated with the breaking and forming of bonds.

In electrochemistry, the enthalpy change can help us understand the overall energy absorbance or release in a reaction. A negative \(\Delta H\) indicates an exothermic reaction, releasing heat to the surroundings, whereas a positive \(\Delta H\) characterizes endothermic reactions, where heat is absorbed from the surroundings. Understanding enthalpy changes is crucial for predicting the temperature dependence of cell potentials, as incorporated into equations representative of electrochemical reactions.
Entropy
Entropy, symbolized as \(\Delta S\), is a measure of the system's disorder or randomness. Changes in entropy can indicate the degree of disorder resulting from a chemical process, such as an electrochemical reaction.

Generally, as entropy increases, so does the disorder of the system. In calculating Gibbs free energy, entropy plays an essential role as it's multiplied by the temperature and subtracted from the enthalpy to determine the spontaneity of a reaction. In electrochemical cells, a positive entropy change suggests greater disorder in the products relative to the reactants, potentially influencing the cell potential, especially when temperature variations are considered.
Nernst Equation
The Nernst equation describes the relationship between the electrochemical cell potential and the concentration of reactants and products. Its standard form is \(E = E^\circ - \frac{RT}{nF}\ln(Q)\), where \(E\) is the cell potential, \(E^\circ\) is the standard cell potential, \(R\) is the gas constant, \(T\) is the temperature in Kelvin, \(n\) is the number of moles of electrons transferred, \(F\) is Faraday's constant, and \(Q\) is the reaction quotient.

The Nernst equation is pivotal in electrochemistry as it accounts for non-standard conditions and enables the calculation of cell potentials at any concentration or pressure, thus providing a real-world application of thermodynamics to electrochemical systems.
Temperature Dependence in Electrochemistry
Temperature has a significant impact on electrochemical reactions, as it affects the kinetic energy of the reacting particles and therefore the reaction rates. It is also intricately related to the Gibbs free energy, enthalpy, and entropy changes that ultimately determine an electrochemical cell's potential.

The dependence of cell potential on temperature can be understood and quantified through the modified Nernst equation, which includes temperature as a variable. Increased temperature often leads to increased cell potential due to the entropy factor that forms part of the Gibbs free energy equation. This behavior underpins the importance of temperature control and monitoring in electrochemical systems.
Electrochemical Cell Potential
Electrochemical cell potential, denoted as \(\mathscr{E}^\circ\), is a measure of the driving force behind an electrochemical reaction. This potential determines whether an electrochemical cell may perform work or require energy to proceed. It is directly related to the free energy change of the reaction via the equation \(\Delta G^\circ = -n F \mathscr{E}^\circ\).

The stability of cell potential with respect to temperature is a crucial factor in the designing of batteries and electrochemical sensors. Cells with minimal temperature sensitivity are more reliable and consistent, ideal for applications where precision and long-term stability are required. The slopes from the Nernst equation provide insight into the design principles for such cells, particularly regarding entropy and enthalpy changes.

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Most popular questions from this chapter

A solution containing \(\mathrm{Pt}^{4+}\) is electrolyzed with a current of 4.00 A. How long will it take to plate out \(99 \%\) of the platinum in 0.50 L of a \(0.010-M\) solution of \(\mathrm{Pt}^{4+} ?\)

Under standard conditions, what reaction occurs, if any, when each of the following operations is performed? a. Crystals of \(\mathrm{I}_{2}\) are added to a solution of NaCl. b. \(\mathrm{Cl}_{2}\) gas is bubbled into a solution of NaI. c. A silver wire is placed in a solution of \(\mathrm{CuCl}_{2}\) d. An acidic solution of \(\mathrm{FeSO}_{4}\) is exposed to air. For the reactions that occur, write a balanced equation and calculate \(\mathscr{E}^{\circ}, \Delta G^{\circ},\) and \(K\) at \(25^{\circ} \mathrm{C}\)

If the cell potential is proportional to work and the standard reduction potential for the hydrogen ion is zero, does this mean that the reduction of the hydrogen ion requires no work?

Gold is produced electrochemically from an aqueous solution of \(\mathrm{Au}(\mathrm{CN})_{2}^{-}\) containing an excess of \(\mathrm{CN}^{-} .\) Gold metal and oxygen gas are produced at the electrodes. What amount (moles) of \(\mathbf{O}_{2}\) will be produced during the production of 1.00 mole of gold?

Consider a galvanic cell based on the following half-reactions: $$\begin{array}{ll} & \mathscr{E}^{\circ}(\mathrm{V}) \\ \mathrm{La}^{3+}+3 \mathrm{e}^{-} \longrightarrow \mathrm{La} & -2.37 \\ \mathrm{Fe}^{2+}+2 \mathrm{e}^{-} \longrightarrow \mathrm{Fe} & -0.44 \\ \hline \end{array}$$ a. What is the expected cell potential with all components in their standard states? b. What is the oxidizing agent in the overall cell reaction? c. What substances make up the anode compartment? d. In the standard cell, in which direction do the electrons flow? e. How many electrons are transferred per unit of cell reaction? f. If this cell is set up at \(25^{\circ} \mathrm{C}\) with \(\left[\mathrm{Fe}^{2+}\right]=2.00 \times 10^{-4} \mathrm{M}\) and \(\left[\mathrm{La}^{3+}\right]=3.00 \times 10^{-3} \mathrm{M},\) what is the expected cell potential?

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