Write balanced equations for each of the processes described below. a. Chromium- \(51,\) which targets the spleen and is used as a tracer in studies of red blood cells, decays by electron capture. b. Iodine-131, used to treat hyperactive thyroid glands, decays by producing a \(\beta\) particle. c. Phosphorus- \(32,\) which accumulates in the liver, decays by \(\beta\) -particle production.

Short Answer

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a. \[^{51}_{24}Cr + e^- \rightarrow ^{51}_{23}V\] b. \[^{131}_{53}I \rightarrow ^{131}_{54}Xe + \beta^-\] c. \[^{32}_{15}P \rightarrow ^{32}_{16}S + \beta^-\]

Step by step solution

01

a. Chromium-51

Chromium-51 undergoes electron capture. The atomic number (Z) decreases by 1 and the mass number (A) remains the same. The initial nucleus is \(^{51}_{24}Cr\), and after electron capture, the resulting nuclide has an atomic number of 23. The balanced equation is: \(^{51}_{24}Cr + e^- \rightarrow ^{51}_{23}V\)
02

b. Iodine-131

Iodine-131 decays by β decay, which means it emits a β particle (an electron). The atomic number (Z) increases by 1 and the mass number (A) remains the same. The initial nucleus is \(^{131}_{53}I\), and after β decay, the resulting nuclide has an atomic number of 54. The balanced equation is: \(^{131}_{53}I \rightarrow ^{131}_{54}Xe + \beta^-\)
03

c. Phosphorus-32

Phosphorus-32 decays by β particle production, which is the same as β decay. The atomic number (Z) increases by 1 and the mass number (A) remains the same. The initial nucleus is \(^{32}_{15}P\), and after β decay, the resulting nuclide has an atomic number of 16. The balanced equation is: \(^{32}_{15}P \rightarrow ^{32}_{16}S + \beta^-\)

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Electron Capture
Electron capture is a type of nuclear decay in which an atomic nucleus absorbs an inner-shell electron from its own electron cloud. This process results in the transformation of a proton into a neutron and simultaneously emits a neutrino, which is a nearly massless particle.

During electron capture, the mass number (A) of the isotope remains the same because the nucleus is simply reconfiguring its particles without adding or losing nucleons. However, the atomic number (Z) decreases by one because one proton (positively charged particle) is converted into one neutron (a neutral particle).

The notation for electron capture involves adding an electron (\(e^-\)) on the reactant side of the nuclear equation. For instance, when Chromium-51 (\( ^{51}_{24}Cr \)) undergoes electron capture, the equation is written as \( ^{51}_{24}Cr + e^- \rightarrow ^{51}_{23}V \), where Vanadium-51 (\( ^{51}_{23}V \) ) is the resulting nuclide.
Beta Decay
Beta decay represents a form of radioactive decay where a beta particle, which is essentially an electron or a positron, is emitted from an atomic nucleus. For beta-minus decay (\( \beta^- \) decay), a neutron is converted into a proton with the emission of an electron and an antineutrino. This causes the atomic number (Z) to increase by one while the mass number (A) remains constant.

In beta-plus decay (\( \beta^+ \) decay), the opposite occurs where a proton is transformed into a neutron with the emission of a positron and a neutrino, causing the atomic number to decrease by one. The general formula for beta-minus decay is \( ^A_ZX \rightarrow ^A_{Z+1}Y + \beta^- \).

As an example, Iodine-131 (\( ^{131}_{53}I \) ) decaying into Xenon-131 (\( ^{131}_{54}Xe \) ) with the emission of a beta particle can be represented as \( ^{131}_{53}I \rightarrow ^{131}_{54}Xe + \beta^- \). Similarly, Phosphorus-32 (\( ^{32}_{15}P \) ) undergoes beta decay to form Sulfur-32 (\( ^{32}_{16}S \) ), which is expressed as \( ^{32}_{15}P \rightarrow ^{32}_{16}S + \beta^- \).
Radioisotope Applications
Radioisotopes have wide-ranging applications in the field of medicine, industry, and scientific research due to their unique radioactive properties. In medical applications, radioactive tracers can help diagnose and treat various health conditions. For example, Chromium-51, with its ability to target the spleen, is utilized in red blood cell studies to understand and diagnose blood disorders.

Another common use is in the treatment of thyroid conditions, where Iodine-131 is administered to patients to manage hyperthyroidism. The beta particles emitted by the decaying Iodine-131 can destroy overactive thyroid cells, thus treating the condition.

In the research domain, radioisotopes such as Phosphorus-32 are used to trace the assimilation of nutrients in organisms. This isotope accumulates in the liver, allowing scientists to monitor liver function and health. These examples demonstrate the critical role radioisotopes play in enhancing our ability to detect and remedy medical challenges, as well as to facilitate advancements in biological research.

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Most popular questions from this chapter

The rate constant for a certain radioactive nuclide is \(1.0 \times\) \(10^{-3} \mathrm{h}^{-1} .\) What is the half-life of this nuclide?

Phosphorus- 32 is a commonly used radioactive nuclide in biochemical research, particularly in studies of nucleic acids. The half-life of phosphorus-32 is 14.3 days. What mass of phosphorus- 32 is left from an original sample of \(175 \mathrm{mg}\) \(\mathrm{Na}_{3}^{32} \mathrm{PO}_{4}\) after 35.0 days? Assume the atomic mass of \(^{32} \mathrm{P}\) is \(32.0 \mathrm{u}\)

The curie (Ci) is a commonly used unit for measuring nuclear radioactivity: 1 curie of radiation is equal to \(3.7 \times 10^{10}\) decay events per second (the number of decay events from 1 g radium in 1 s). A 1.7 -mL sample of water containing tritium was injected into a 150 -lb person. The total activity of radiation injected was \(86.5 \mathrm{mCi}\). After some time to allow the tritium activity to equally distribute throughout the body, a sample of blood plasma containing \(2.0 \mathrm{mL}\) water at an activity of \(3.6 \mu \mathrm{Ci}\) was removed. From these data, calculate the mass percent of water in this 150 -lb person.

A rock contains \(0.688 \mathrm{mg}^{206} \mathrm{Pb}\) for every \(1.000 \mathrm{mg}\) \(^{238} \mathrm{U}\) present Assuming that no lead was originally present, that all the \(^{206} \mathrm{Pb}\) formed over the years has remained in the rock, and that the number of nuclides in intermediate stages of decay between \(^{238} \mathrm{U}\) and \(^{206} \mathrm{Pb}\) is negligible, calculate the age of the \(\text { rock. For }^{238} \mathbf{U}, t_{1 / 2}=4.5 \times 10^{9} \text { years. }\)

Iodine-131 has a half-life of 8.0 days. How many days will it take for 174 g of \(^{131}\) I to decay to 83 g of \(^{131}\) I?

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