Write balanced equations describing the reaction of lithium metal with each of the following: \(\mathrm{O}_{2}, \mathrm{S}, \mathrm{Cl}_{2}, \mathrm{P}_{4}, \mathrm{H}_{2}, \mathrm{H}_{2} \mathrm{O},\) and HCl.

Short Answer

Expert verified
The balanced equations for the reaction of lithium with the given substances are as follows: 1. \(\mathrm{Li} + \mathrm{O}_{2}\): \[4 \mathrm{Li} + \mathrm{O}_{2} \rightarrow 2 \mathrm{Li}_{2}\mathrm{O}\] 2. \(\mathrm{Li} + \mathrm{S}\): \[2 \mathrm{Li} + \mathrm{S} \rightarrow \mathrm{Li}_{2}\mathrm{S}\] 3. \(\mathrm{Li} + \mathrm{Cl}_{2}\): \[2 \mathrm{Li} + \mathrm{Cl}_{2} \rightarrow 2 \mathrm{Li}\mathrm{Cl}\] 4. \(\mathrm{Li} + \mathrm{P}_{4}\): \[12 \mathrm{Li} + \mathrm{P}_{4} \rightarrow 4 \mathrm{Li}_{3}\mathrm{P}\] 5. \(\mathrm{Li} + \mathrm{H}_{2}\): \[2 \mathrm{Li} + \mathrm{H}_{2} \rightarrow 2 \mathrm{Li}\mathrm{H}\] 6. \(\mathrm{Li} + \mathrm{H}_{2}\mathrm{O}\): \[2 \mathrm{Li} + 2 \mathrm{H}_{2} \mathrm{O} \rightarrow 2 \mathrm{Li}\mathrm{OH} + \mathrm{H}_{2}\] 7. \(\mathrm{Li} + \mathrm{H}\mathrm{Cl}\): \[2 \mathrm{Li} + 2 \mathrm{H}\mathrm{Cl} \rightarrow 2 \mathrm{Li}\mathrm{Cl} + \mathrm{H}_{2}\]

Step by step solution

01

Reaction with \(\mathrm{O}_{2}\)

Lithium reacts with oxygen to form lithium oxide (Li2O). The balanced equation is: \[4 \mathrm{Li} + \mathrm{O}_{2} \rightarrow 2 \mathrm{Li}_{2}\mathrm{O}\]
02

Reaction with \(\mathrm{S}\)

Lithium reacts with sulfur to form lithium sulfide (Li2S). The balanced equation is: \[2 \mathrm{Li} + \mathrm{S} \rightarrow \mathrm{Li}_{2}\mathrm{S}\]
03

Reaction with \(\mathrm{Cl}_{2}\)

Lithium reacts with chlorine gas to form lithium chloride (LiCl). The balanced equation is: \[2 \mathrm{Li} + \mathrm{Cl}_{2} \rightarrow 2 \mathrm{Li}\mathrm{Cl}\]
04

Reaction with \(\mathrm{P}_{4}\)

Lithium reacts with white phosphorus (\(\mathrm{P}_{4}\)) to form lithium phosphide (Li3P). The balanced equation is: \[12 \mathrm{Li} + \mathrm{P}_{4} \rightarrow 4 \mathrm{Li}_{3}\mathrm{P}\]
05

Reaction with \(\mathrm{H}_{2}\)

Lithium reacts with hydrogen to form lithium hydride (LiH). The balanced equation is: \[2 \mathrm{Li} + \mathrm{H}_{2} \rightarrow 2 \mathrm{Li}\mathrm{H}\]
06

Reaction with \(\mathrm{H}_{2} \mathrm{O}\)

Lithium reacts with water to form lithium hydroxide (LiOH) and hydrogen gas. The balanced equation is: \[2 \mathrm{Li} + 2 \mathrm{H}_{2} \mathrm{O} \rightarrow 2 \mathrm{Li}\mathrm{OH} + \mathrm{H}_{2}\]
07

Reaction with HCl

Lithium reacts with hydrochloric acid to form lithium chloride (LiCl) and hydrogen gas. The balanced equation is: \[2 \mathrm{Li} + 2 \mathrm{H}\mathrm{Cl} \rightarrow 2 \mathrm{Li}\mathrm{Cl} + \mathrm{H}_{2}\]

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Most popular questions from this chapter

While selenic acid has the formula \(\mathrm{H}_{2} \mathrm{SeO}_{4}\) and thus is directly related to sulfuric acid, telluric acid is best visualized as \(\mathrm{H}_{6} \mathrm{TeO}_{6}\) or \(\mathrm{Te}(\mathrm{OH})_{6}\) a. What is the oxidation state of tellurium in \(\operatorname{Te}(\mathrm{OH})_{6} ?\) b. Despite its structural differences with sulfuric and selenic acid, telluric acid is a diprotic acid with \(\mathrm{p} K_{\mathrm{a}_{1}}=7.68\) and \(\mathrm{p} K_{\mathrm{a}_{2}}=11.29 .\) Telluric acid can be prepared by hydrolysis of tellurium hexafluoride according to the equation $$\operatorname{TeF}_{6}(g)+6 \mathrm{H}_{2} \mathrm{O}(l) \longrightarrow\operatorname{Te}(\mathrm{OH})_{6}(a q)+6 \mathrm{HF}(a q)$$ Tellurium hexafluoride can be prepared by the reaction of elemental tellurium with fluorine gas:$$\operatorname{Te}(s)+3 \mathrm{F}_{2}(g) \longrightarrow \operatorname{Te} \mathrm{F}_{6}(g)$$.If a cubic block of tellurium (density \(=6.240 \mathrm{g} / \mathrm{cm}^{3}\) ) measuring \(0.545 \mathrm{cm}\) on edge is allowed to react with 2.34 L fluorine gas at 1.06 atm and \(25^{\circ} \mathrm{C}\), what is the \(\mathrm{pH}\) of a solution of \(\mathrm{Te}(\mathrm{OH})_{6}\) formed by dissolving the isolated \(\operatorname{Te} \mathrm{F}_{6}(g)\) in \(115 \mathrm{mL}\) solution? Assume \(100 \%\) yield in all reactions.

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