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Chapter 19: Problem 56

Complete and balance each of the following reactions. a. the reaction between sulfur dioxide gas and oxygen gas b. the reaction between sulfur trioxide gas and water c. the reaction between concentrated sulfuric acid and su\(\operatorname{crose}\left(\mathrm{C}_{12} \mathrm{H}_{22} \mathrm{O}_{11}\right)\)

Short Answer

Expert verified
The short version of the answer for the three reactions is as follows: a. \(SO_2 (g) + O_2 (g) \rightarrow 2 SO_3 (g)\) b. \(SO_3 (g) + H_2O (l) \rightarrow H_2SO_4 (l)\) c. \(2 H_2SO_4 (l) + C_{12}H_{22}O_{11} (s) \rightarrow 12 CO_2 (g) + 18 H_2O (l) + 2 H_2S (g)\)

Step by step solution

01

Write the unbalanced chemical equation

SO2 (g) + O2 (g) → SO3 (g)
02

Determine the number of atoms for each element

On the left side, we have one S atom, three O atoms. On the right side, we have one S atom and three O atoms.
03

Balance the atoms

In this case, the equation is already balanced because there are the same number of atoms of each element on both sides.
04

Verify that the equation is balanced

The balanced equation is: SO2 (g) + O2 (g) → 2 SO3 (g) b. Reaction between sulfur trioxide gas and water
05

Write the unbalanced chemical equation

SO3 (g) + H2O (l) → H2SO4 (l)
06

Determine the number of atoms for each element

On the left side, we have one S atom, four O atoms, and two H atoms. On the right side, we have one S atom, four O atoms, and two H atoms.
07

Balance the atoms

In this case, the equation is already balanced because there are the same number of atoms of each element on both sides.
08

Verify that the equation is balanced

The balanced equation is: SO3 (g) + H2O (l) → H2SO4 (l) c. Reaction between concentrated sulfuric acid and sucrose
09

Write the unbalanced chemical equation

H2SO4 (l) + C12H22O11 (s) → CO2 (g) + H2O (l) + H2S (g)
10

Determine the number of atoms for each element

On the left side, we have one S atom, 15 O atoms, 14 H atoms, and 12 C atoms. On the right side, we have one S atom, an unknown number of O atoms, an unknown number of H atoms, and an unknown number of C atoms.
11

Balance the atoms

First, we will balance the C atoms. Since there are twelve C atoms in the compound sucrose, we need twelve CO2 molecules in the balanced equation. H2SO4 (l) + C12H22O11 (s) → 12 CO2 (g) + H2O (l) + H2S (g) Next, we will balance the H atoms. There are 22 H atoms in the compound sucrose and 4 H atoms in the products, so we need 18 H2O molecules in the balanced equation. H2SO4 (l) + C12H22O11 (s) → 12 CO2 (g) + 18 H2O (l) + H2S (g) Finally, we will balance the O atoms. There are 11 O atoms in the compound sucrose and 28 O atoms in the products, so we need one more H2SO4 molecule in the balanced equation. 2 H2SO4 (l) + C12H22O11 (s) → 12 CO2 (g) + 18 H2O (l) + 2 H2S (g)
12

Verify that the equation is balanced

The balanced equation is: 2 H2SO4 (l) + C12H22O11 (s) → 12 CO2 (g) + 18 H2O (l) + 2 H2S (g)

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Most popular questions from this chapter

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